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Vsevolod [243]
3 years ago
13

Why would it require greater force to start a refrigerator moving than to start a dog moving?

Physics
1 answer:
3241004551 [841]3 years ago
6 0
It would require a greater force to start a refrigerator moving than to start a dog moving because the mass of a refrigerator is greater than the mass of a dog. Basically, the force to start an object is proportional to the normal force which is equivalent to the weight of the object. 
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A monk is sitting atop a mountain in complete rest in meditation. What is the kinetic Energy of the monk? (assume mass of 65 kg
Genrish500 [490]

Answer:

no kinetic energy

hope this helps! :-D

Explanation:

the monk is not moving

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Atoms are split at power plant to create electricity*
Rudiy27

Answer:

B. Nuclear to Electrical

Explanation:

Atoms are split at power plants to create electricity. The energy conversion in this process is from nuclear to electrical energy.

  • When atoms are split, nuclear energy is released.
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  • The nuclear energy released is expressed as heat energy.
  • This energy is used to heat water in boilers when produces steam that are used to drive the movement of turbines.
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Which of the following can influence one’s ability to detect stimuli and increase one’s responsiveness to stimuli in dangerous s
Keith_Richards [23]
The correct answer is Response Criteria.
6 0
3 years ago
Read 2 more answers
How fast must a 100 kg object be going in order for it to stop a 200 kg object traveling at 10 km/hr when the two objects collid
hichkok12 [17]
P1i+p2i =p1f +p2f where p is momentum and i denotes initial, f denotes final, and 1 and 2 refers to the object number. If the object stops, their velocity is 0 and p1f and p2f also equal 0.

p=mass x velocity

We have p1i=-p2i

100v1i=-(200) (-10÷3.6)


Note: 10÷3.6 is 10km/hr in m/s
Note: The velocity of the second object ifs negative because I said the velocity of the first object was positive and the second object is travelling in the opposite direction

So v1i=20/3.6=5.56m/s
8 0
3 years ago
A small box of mass m1 is sitting on a board of mass m2 and length L. The board rests on a frictionless horizontal surface. The
inn [45]

Answer: Fmin = (m₁ + m₂) μsg

Explanation:

To begin, we would first define the parameters given in the question.

Mass of the box = m₁

Mass of the board = m₂

We have a Frictionless surface given that Fr is acting as the frictional force between the box and the board.

from our definition of force, i.e. the the frictional force against friction experienced by the box, we have

Fr = m₁a ...................(1)

Also considering the force between the box and the board gives;

Fr = μsm₁g .................(2)

therefore equating both (1) and (2) we get

m₁a = μsm₁g

eliminating like terms we get

a = μsg

To solve for the minimum force Fmin  that must be applied to the board in order to pull the board out from under the box, we have

Fmin  = (m₁ + m₂) a  ...........(3)

where a = μsg, substituting gives

Fmin = (m₁ + m₂) μsg

cheers i hope this helps

4 0
3 years ago
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