Answer:
This is proved by ASA congruent rule.
Step-by-step explanation:
Given KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. we have to prove that A is equidistant from LM and KN i.e we have to prove that AP=AQ
we know that the diagonals of parallelogram bisect each other therefore the the bisectors of ∠K and ∠L must be the diagonals.
In ΔAPN and ΔAQL
∠PNA=∠ALQ (∵alternate angles)
AN=AL (∵diagonals of parallelogram bisect each other)
∠PAN=∠LAQ (∵vertically opposite angles)
∴ By ASA rule ΔAPN ≅ ΔAQL
Hence, by CPCT i.e Corresponding parts of congruent triangles PA=AQ
Hence, A is equidistant from LM and KN.
You'll need to add 2 3/7 to <span> 3 4/7 to make 6.
3 + 2 = 5 4/7 + 3/7 = 7/7 =1
5+1=6</span>
The answer is 68cm^2. Hope this helps!
Answer:
EF= 18 in. , m<F=134'
Step-by-step explanation:
This ones for the boys with the booming system, top down ac with the cooling sytem