Question

The perimeter of a rectangle is 160 feet. If the length of the rectangle is 28 feet more than the width, what are the dimensions of the rectangle?

Answer 1

Answer:

width = 26 ft

length = 54 ft

Step-by-step explanation:

perimeter = 160 ft

width = x

length = x + 28

Perimeter = 2(width) + 2(length)

$2x + 2(x + 28) = 160 \\ 2x + 2x + 56 = 16 0\\ 4x = 160 - 56 \\ x = \frac{104}{4} \\ x = 26$

width = x = 26

length = x + 28 = 26 + 28 = 54