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Vladimir79 [104]
3 years ago
6

Okay this is my last question please help

Chemistry
1 answer:
Anna35 [415]3 years ago
8 0

Answer:

Okay this is my last question please help

I raised the points because I really need help so please don't put a random answer just to get the points thank you!

points is so big thaks

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Consider the chemical reaction represented below
hjlf

Answer:

D

Explanation:

4 0
4 years ago
The molality of a solution that is made by dissolving a certain mass of benzene in 20.6g of carbon tetrachloride is 0.529m. How
antiseptic1488 [7]
Molality of solution = 0.529 m

mass solvent in kg = 20.6 g => 20.6 / 1000 => 0.0206 kg

number of moles = molality x mass solvent

= 0.529 x 0.0206 => <span> 0.0108 mol benzene 
</span>
hope this helps!

6 0
3 years ago
Read 2 more answers
If you burn 59.1 g of hydrogen and produce 528 g of water , how much oxygen is reacted
shtirl [24]
Hydrogen + oxygen --> water
59,1g + x = 528g
528g - 59,1 = x
x = 468,9g
8 0
3 years ago
At 35 C, a sample of gas has a volume of 256 ml and a pressure of 720.torr. What would the volume
Natalija [7]

Answer: Volume would be 196.15 mL if the temperature were changed to 22^{o}C and the pressure to 1.25 atmospheres.

Explanation:

Given: T_{1} = 35^{o}C = (35 + 273) K = 308 K,     V_{1} = 256 mL,    

P_{1} = 720 torr (1 torr = 0.00131579 atm) = 0.947368 atm

T_{1} = 22^{o}C = (22 + 273) K = 295 K,       P_{2} = 1.25 atm  

Formula used to calculate volume is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{1 atm \times 256 mL}{308 K} = \frac{1.25 atm \times V_{2}}{295 K}\\V_{2} = 196.15 mL

Thus, we can conclude that the volume would be 196.15 mL if the temperature were changed to 22^{o}C and the pressure to 1.25 atmospheres.

4 0
3 years ago
How many moles of electrons are transferred when 2.0 moles of aluminum metal react with excess copper(II) nitrate in aqueous sol
mojhsa [17]

Moles of electrons:

The moles of electrons that are transferred are 12F

A balanced equation:

2 moles of Aluminium metal react with excess copper(II) nitrate.

2Al + 3Cu{(NO_3)}_2  \rightarrow 2Al{(NO_3)}_3 +3 Cu

Given:

Moles of Aluminium = 2

As Aluminium goes from 0 to +3 oxidation state

Al \rightarrow Al^{3+} + 3e^-

And copper goes from +2 to 0

Cu^{2+} + 2e^-\rightarrow Cu

On balancing the number of electrons we get:

For 1 mole of Al 6e^- is required.

Therefore for 2 moles of Al,

Total (2\times6)F mole of electrons

Where F= Faraday's constant= 96500 C

So, 12F moles of electrons are transferred.

Learn more about Faraday's Law here,

brainly.com/question/27985929

#SPJ4

4 0
2 years ago
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