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katovenus [111]
3 years ago
8

Which of the following could be the name of the substance in box ‘c` choose only one box:

Chemistry
2 answers:
11Alexandr11 [23.1K]3 years ago
3 0
A is the answer i hope it helps
Drupady [299]3 years ago
3 0

I Think it is Carbon Monoxide Because of the Following Reasons :

\clubsuit  From the Picture, We can Notice that the Both Atoms are Approximately of Same Size or Diameter. Carbon and Oxygen have Approximately Same Diameter.

\clubsuit  It Cannot be Nitrogen, Because the Color of Atoms is Different. So, They must be of Different Element's Atoms.

\clubsuit  It Cannot be Krypton, Because Krypton is a Noble Gas it does not Pair up with other Atoms.

\clubsuit  It Cannot be Hydrogen Chloride, Because There is a Big Difference between the Size of Hydrogen and Chlorine Atom.

\clubsuit  It Cannot be Sulphur dioxide, Because Sulphur dioxide Contains 3 Atoms. One Sulphur and Two Oxygen Atoms.

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25 g of NH, is mixed with 4 moles of O, in the given reaction:
FromTheMoon [43]

Answer:

a. NH3 is limiting reactant.

b. 44g of NO

c. 40g of H2O

Explanation:

Based on the reaction:

4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(l)

4 moles of ammonia reacts with 5 moles of oxygen to produces 4 moles of NO and 6 moles of water.

To find limiting reactant we need to find the moles of each reactant and using the balanced equation find which reactant will be ended first. Then, with limiting reactant we can find the moles of each reactant and its mass:

<em>a. </em><em>Moles NH3 -Molar mass. 17.031g/mol-</em>

25g NH3*(1mol/17.031g) = 1.47moles NH3

Moles O2 = 4 moles

For a complete reaction of 4 moles of O2 are required:

4mol O2 * (4mol NH3 / 5mol O2) = 3.2 moles of NH3.

As there are just 1.47 moles, NH3 is limiting reactant

b. Moles NO:

1.47moles NH3 * (4mol NO/4mol NH3) = 1.47mol NO

Mass NO -Molar mass: 30.01g/mol-

1.47mol NO * (30.01g/mol) = 44g of NO

c. Moles H2O:

1.47moles NH3 * (6mol H2O/4mol NH3) = 2.205mol H2O

Mass H2O -Molar mass: 18.01g/mol-

2.205mol H2O * (18.01g/mol) = 40g of H2O

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