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n200080 [17]
3 years ago
6

YØLØ ♚ Plz help me i will mark brainliest

Mathematics
1 answer:
AleksandrR [38]3 years ago
3 0

Answer:

10

Step-by-step explanation:I had this

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the length of a rectangle is 4 more than 3 times the width. If the perimeter of the rectangle is 18.4cm, what is the area of the
antoniya [11.8K]

Answer:

A = 10.27cm²

Step-by-step explanation:

Let's represent the width as x,

therefore since the length is 4 more than 3 times the width, it can be represent as 3x + 4,   Perimeter = 18.4cm

Perimeter of a rectangle = 2(L + B)

18.4= 2(3x+4+x)\\18.4= 6x+8+2x\\18.4-8=6x+2x\\10.4=8x\\x=\frac{10.4}{8}\\x=1.3

width = 1.3cm

Length = 3x + 4 = 3*1.3 + 4 = 7.9cm

Area of a rectangle = length x width

A = 7.9 * 1.3 = 10.27cm²

6 0
2 years ago
Read 2 more answers
SOMEONE PLEASE HELP ME ASAP THIS IS ALMOST DUE ILL MARK BRAINLIEST!!!!
makkiz [27]

Answer:

153

Step-by-step explanation:

If the table adds up to 20 and opened toe counts for 45% of the total. then 45% of 340 is 153 !

3 0
2 years ago
What is the solution(s) to the system of equations y = x² +4 and y = 2x + 4
bija089 [108]

Answer:

(x,y) = (0,4)~ \text{and}~ (x,y) = (2,8)

Step by step explanation:

y = x^2 +4~~~~~~~~~...(i)\\\\y = 2x +4~~~~~~~~~...(ii)\\\\\text{From (i) and (ii):}\\\\~~~~~~x^2 +4 = 2x+4\\\\\implies x^2 = 2x\\\\\implies x^2 -2x = 0\\\\\implies x(x-2) = 0\\\\\implies x =0,~ x = 2

\text{Substitute x = 0 in eq (i):}\\\\y = 0^2 +4 = 4\\\\\text{Substitute x = 2 in eq (i):}\\\\y=2^2+4 = 4+4 = 8\\\\\text{Hence,}~ (x,y)= \{(2,8), (0,4)\}

3 0
1 year ago
Show that the maximum rate of change, with respect to radius, of the volume of a deflating balloon is four times the sphere's in
dmitriy555 [2]

Step-by-step explanation:

Let's say R is the initial radius of the sphere, and r is the radius at time t.

The volume of the sphere at time t is:

V = 4/3 π r³

Taking derivative with respect to radius:

dV/dr = 4π r²

This is a maximum when r is a maximum, which is when r = R.

(dV/dr)max = 4π R²

This is 4 times the sphere's initial great circle area, but not the great circle circumference.  The problem statement contains an error.

7 0
3 years ago
In a​ triangle, the measure of the first angle is twice the measure of the second angle. the measure of the third angle is 80 de
Furkat [3]
1st angle = 2 * 2nd angle
3rd angle = 2nd angle + 80

1st angle = 2x 

2nd angle  = x
3rd angle = 80 + x


2x + x + 80 + x = 180
4x = 100
x = 25

1st angle = 50
2nd angle = 25
3rd angle = 105



3 0
3 years ago
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