Ammonium Nitrate has the formula NH4NO3, and has a formula weight of 80.043 grams/mole. We can convert the amount in the problem to moles using this conversion factor. Divide 435 by 80.043 to find the number of moles.
435/80.043 = 5.435
This amount of Ammonium Nitrate contains 5.44 moles of substance, adjusted for significant figures.
Answer:
-37.63KJ
Explanation:
First, we write an equation of reaction:
H + Br ——-> HBr
Now we are told that 155g of HBr is formed. We can calculate the number of moles of HBr formed as follows:
We simply divide the mass of the HBr formed by the molar mass of HBr. The molar mass of HBr is 81g/mol
The number of moles of HBr formed is thus 81/155 = 0.52 moles
The amount of heat released is thus 0.52 * (-72) = -37.63KJ
Answer/Explanation:
62.559%
mass of an element X 100%
mass of the compound
Scientific Notation: 3.45 x 10^5
E Notation: 3.45e5
