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professor190 [17]
4 years ago
6

Convert each into decimal form.a) 1.56× 10^3b) 0.56×10-4​

Chemistry
1 answer:
Lera25 [3.4K]4 years ago
3 0

Answer: A = 1560

               B = 1.6

Explanation: brainlest please

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Phosphorus-32 is radioactive and has a half life of 14.3 days. Calculate the activity of a 3.5mg sample of phosphorus-32. Give y
Andreyy89

Answer:

The activity of P-32 is 3.7x10¹³ becquerels = 1.0x10³ curies.

Explanation:

The activity of P-32 can be calculated with the following equation:

A = \lambda N   (1)

Where:

N: is the number of atoms of P-32

λ: is the decay constant

We can find the number of atoms of P-32 as follows:

N = \frac{N_{A}*m}{M}  (2)

Where:

N_{A}: is the Avogadro's number = 6.022x10²³ atoms/mol

m: is the mass of P-32 = 3.5x10⁻³ g

M: is the molar mass of the radionuclide (P-32) = 32 g/mol    

Now, the decay constant is given by:

\lambda = \frac{ln(2)}{t_{1/2}}   (3)

Where:

{t_{1/2}}: is the half-life of P-32 = 14.3 days

Finally, we can find the activity of P-32 by entering equations (2) and (3) into (1):

A = \lambda N = \frac{ln(2)}{t_{1/2}}*\frac{N_{A}*m}{M} = \frac{ln(2)}{14.3 d*\frac{24 h}{1 d}*\frac{3600 s}{1 h}}*\frac{6.022 \cdot 10^{23} mol^{-1}*3.5 \cdot 10^{-3} g}{32 g/mol} = 3.7 \cdot 10^{13} dis/s      

Since a becquerel (Bq) is defined as a disintegration (dis) per second, the activity in Bq is:

A = 3.7 \cdot 10^{13} Bq

And, since a Curie (Ci) is 3.7x10¹⁰ Bq, the activity in Ci is:

A = 3.7 \cdot 10^{13} Bq*\frac{1 Ci}{3.7 \cdot 10^{10} Bq} = 1.0 \cdot 10^{3} Ci

Therefore, the activity of P-32 is 3.7x10¹³ becquerels = 1.0x10³ curies.  

               

I hope it helps you!

8 0
3 years ago
Given the law of conservation of energy, what happens when a 200°C iron bar is placed in thermal contact with a 30°C block of wo
ra1l [238]

Answer:

A Energy leaves the iron bar and enters the wood until the temperature are equal.

Explanation:

According to the law of conservation of energy or the first law thermodynamics energy neither be created nor destroyed, energy is transferred from one form to another form.

5 0
4 years ago
A solution is made by dissolving 85.0 mL of sodium fluoride to water until the final volume is 350.0 mL. Identify the solute in
Natasha_Volkova [10]

Answer:

  • <u><em>Sodium fluoride</em></u>

Explanation:

A <em>solution </em>is constituted by two parts: the solute and the solvent (there may be more than 1 solute and more than 1 solvent, but that is not the key of the answer).

<em>Solute</em> is the substace that is dissolved and it is in less amount than the solvent.

<em>Solvent</em> is the substance that can dissolve the solute and it is a greater amount than the solute.

In the given solution:

  • <em>sodium fluoride</em>, <em>85.0 mL</em>, is the solute,
  • <em>water</em>, <em>350.0 mL</em> is the solvent, and
  • the mixture of both substances is the solution.
8 0
3 years ago
Which of the following statements is true?
slavikrds [6]
Number 3 is the answer
3 0
4 years ago
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The ph of an acid solution is 6.20. Calculate the ka for the acid. The acid concentration is 0.010 m.
djverab [1.8K]

Answer:

620

Explanation:

7 0
4 years ago
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