72g H2O x 1 mol H2O/18.02g H2O = 3.99 mol H2O
Q = 1.161 J/kg of heat is required to melt 99.9 g of solid acetic acid (HCH,CO2). Q = mL(Latent heat is the energy emitted or absorbed by a body while changing it state ). (Latent heat is the energy released or absorbed by a body while changing it state ).
<h3>How to fix?</h3>
Apply the equation Q = mL where:
Energy is Q. (J)
m = Mass (g)
L = Acetic acid's latent heat of fusion 192(J/g) = J/g
Q is equal to 0.099 kg times 11.73 kj/mol.
Q = 1.161J/kg.
<h3>What is latent heat, and what varieties are there?</h3>
Latent heat is the amount of energy that a substance experiencing a change in state, such as ice turning into water or water turning into steam, can absorb or release while maintaining a constant temperature and pressure. Types: The material exists in three states: solid, liquid, and gaseous.
<h3>What does "sensible heat" mean?</h3>
Heat that can actually be felt is considered to be sensible heat. Instead of the phase shifting, energy is what causes the temperature to vary as it moves from one system to another. For instance, it warms the water instead of melting the ice.
Learn more about specific heat on:
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Answer:
The answer is D; 1.45 x 10^-4
Answer:
See explanation
Explanation:
Polymerization is the process whereby two or more monomers link together to form a compound of high molecular mass called a polymer.
There are two kinds of polymers;
-Addition polymers
-Condensation polymers
Addition polymers are formed by the joining of two or more monomers to form a polymer without the elimination of a small molecule.
Condensation polymers are formed by the joining of two or more molecules to form polymers with the elimination of a small molecule.
The main difference between polyethene and polyester is that polyethene is an addition polymer while polyester is a condensation polymer.
In polyethene, ethene molecules are joined together having the repeating unit as [-CH2-CH2-]n.
In polyester, the polymer arises from the reaction of carboxylic acid and an alcohol and loss of water molecules.
H₂CO₃ ⇔ HCO₃⁻ + H⁺
I 0.160 0 0
C -x +x +x
E 0.160-x +x +x
Ka1 = [HCO₃⁻][H⁺] / [H₂CO₃]
4.3 x 10⁻⁷ = x² / (0.160-x) (x is neglected in 0.160-x = 0.160)
x² = 6.88 x 10⁻⁸
x = 2.62 x 10⁻⁴
HCO₃⁻ ⇔ CO₃⁻² + H⁺
I 2.62 x 10⁻⁴ 0 2.62 x 10⁻⁴
C -x +x +x
E 2.62 x 10⁻⁴ - x +x 2.62 x 10⁻⁴ + x
Ka2 = [CO₃⁻²][H⁺] / [HCO₃⁻]
5.6 x 10⁻¹¹ = x(2.62 x 10⁻⁴ + x) / (2.62 x 10⁻⁴ - x)
x = 5.6 x 10⁻¹¹
Thus,
[H₂CO₃] = 0.160 - (2.62 x 10⁻⁴) = 0.16 M
[HCO₃⁻] = 2.62 x 10⁻⁴ - ( 5.6 x 10⁻¹¹) = 2.6 x 10⁻⁴ M
[CO₃⁻²] = 5.6 x 10⁻¹¹ M
[H₃O⁺] = 2.62 x 10⁻⁴ + 5.6 x 10⁻¹¹ = 2.6 x 10⁻⁴ M
[OH⁻] = 3.8 x 10⁻¹¹
