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Degger [83]
3 years ago
13

Whats the molar mass of c6h6

Chemistry
1 answer:
N76 [4]3 years ago
3 0
B I did this on a test
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Liquid nitrogen has a density of 0.808 g/mL and boils at 77 K. Researchers often purchase liquid nitrogen in insulated 185 L tan
Serga [27]

Answer:

37.14 %

Explanation:

Using the equation, mass, M = D1 * V1

= D2 * V2

Where,

D1 = density of the liquid Nitrogen

D2 = density of gaseous Nitrogen

V1 = volume of the liquid Nitrogen

V2 = volume of the gaseous Nitrogen

Calculating V2,

0.808 * 185 = 1.15 * V2

Volume of Nitrogen after expansion = 129.98 m3.

Volume = L * b * h

= 10 * 10 * 3.5

Volume of the room = 350 m3.

Fraction of air = volume of Nitrogen after expansion/volume of the room * 100

= 129.98/350 *100

= 37.14 %

5 0
3 years ago
URGENT HELP PLEASE balance equation !20 points!
yKpoI14uk [10]
Au^2S^3+ 3H^2 = 2Au + 3H^2S
5 0
3 years ago
Zn + 2HCI --> ZnCl2 + H2
Elena-2011 [213]
Moles= mass\ relative formula mass(Ar)
moles of zinc= 7.9/30= 0.263
so we have 0.263 moles of zinc, and you need twice the amount of chlorine so therefore 0.526moles of chlorine= 0.526x 17=8.942g of chlorine
i cba to work the rest out but the most reasonable answer is 0.24 mol however if you need to use working outs, use the formula i provided earlier
8 0
3 years ago
The diagram shows a simple lipid.
kifflom [539]
This is not a phospholipid as it does not contain a phosphate group at the end of the chain, and is not a triglyceride as there is no glyceryl moiety. Each carbon bonded to hydrogens makes the maximum number of C-H bonds possible, therefore there are no multiple bonds between carbons and the lipid is saturated. Therefore the answer is A.
Hope this helps!
7 0
3 years ago
Read 2 more answers
The reaction of pyrrole with bromine forms predominantly __________. View Available Hint(s) The reaction of pyrrole with bromine
xenn [34]

Answer:

a) 2-bromopyrrole

Explanation:

Our options for this questions are:

a) 2-bromopyrrole

b) 2,3-dibromopyrrole

c) N-bromopyrrole

d) 3-bromopyrrole

To understand how the reaction works we have to start with the <u>resonance structures</u>. (Figure 1), on these structures, we will obtain a n<u>egative charge on carbon 2</u> in the pyrrole ring, therefore on this carbon we can generate an attack to an electrophile.

The second step is to check how the mechanism take place. An <u>electrophile is generated</u> by the Br_2 and FeBr_3. This electrophile can be <u>attacked</u> by the negative charge on carbon 2 producing the 2-bromopyrrole. (See figure 2).

I hope it helps!

5 0
3 years ago
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