Whats the molar mass of c6h6

The compound HA is an acid that is soluble in water which of the beakers in the picture shows HA behaving as a weak acid in wate

lesya692 [45]

HA is a weak acid so there should be little amount of HA and then H+ and A- in the beaker so the last one is true a weak acid never converts completely to H+ and A-

6 0

3 years ago

Consider the following balanced reaction. How many grams of water are required to form 75.9 g of HNO3? Assume that there is exce

adoni [48]

Answer:

The answer is "10.84 g".

Explanation:

The formula for calculating the number for moles:

$\text{Number of moles }= \frac{\ Mass}{ \ molar \ mass }$

In the given acid nitric:

Owing to the nitric acid mass = $75.9 g$

Nitric acid molar weight $= 63\ \frac{g}{mol}$

If they put values above the formula, they receive:

$\text{moles in nitric acid} = \frac{75.9}{63}$

$=1.204 \ mol$

In the given chemical equation:

$3 NO_2 \ (g) + H_2O \ (l) \longroghtarrow 2 HNO_3 \ (aq) + NO\ (g)$

In this reaction, 2 mols of nitric acid are produced by 1 mole of water.

So, 1.204 moles of nitric acid will be produced:

$= \frac{1}{2} \times 1.204$

$=0.602\ \ \text{mol of water}.$

We are now using Equation 1 in determining the quantity of water:

Water moles $= 0.602\ mol$

Water weight molar $= 18.02 \ \frac{g}{mol}$

$\to 0.602 = \frac{\text{mass of mols}}{ 18.02}\\\\\to \text{mass of mols} = 0.602 \times 18.02\\\\$

$=10.84 \ g$

8 0

3 years ago

Will Mark Brainliest!!

Vikentia [17]

Answer -

1.4 g water

Hope this helps! ^^

8 0

3 years ago

At a temperature of 273 K, a 400.-milliliter gas sample has a pressure of 760. millimeters of mercury. If the pressure is change

KatRina [158]

Answer:

188.03K

Explanation:

The following data were obtained from the question:

T1 (initial temperature) =273K

V1 (initial volume) = 400mL

P1 (initial pressure) = 760mmHg

P2 (final pressure) = 380mmHg

V2 (final volume) = 551mL

T2 (final temperature) =?

Applying the general gas equation P1V1/T1 = P2V2/T2, the final temperature of the gas can be obtained as follow:

P1V1/T1 = P2V2/T2

760 x 400/273 = 380 x 551/T2

Cross multiply to express in linear form as shown below:

760 x 400 x T2 = 273 x 380 x 551

Divide both side by 760 x 400

T2 = (273 x 380 x 551)/(760 x 400)

T2 = 188.03K.

Therefore, at a temperature of 188.03K, the gas sample will have a volume of 551mL

3 0

3 years ago

Two black-fur mice are bred, and have the litter shown below. What is the most likely explanation for the presence of the white-

Kisachek [45]

Most of the litter shown will be black, most likely only one mouse will be white furred.

4 0

3 years ago