If P(not A) = 0.18 and P(A and B) = 0.44, what is P(B given A)?

Mathematics

1 answer:

pickupchik [31]3 years ago

3 0

p(not A)=0.18

p(A&B)= 0.44

A= 0.44- 0.18

= 0.26

P(B given A)= 0.26+0.18+0.44

=0.7

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