The quantity of 0.001 m aq naoh needed to neutralize the hcl produced by complete solvolysis is 200 ml.
Solvolysis is a type of nucleophilic substitution or elimination wherein the nucleophile is a solvent molecule. function of SN1 reactions, solvolysis of a chiral reactant provides the racemate.
Calculation :-
using the titration equation,
M₁V₁ = M₂V₂
substituting values
V₁ = M₂ V₂/M₁
= 0.2 × 10 ml /0.01
= 2/0.01 ml
= 200 ml.
A reaction in which the solvent is a reactant, and turns into part of the response product. Hydrolysis of tert-butyl chloride; solvent = water. Fischer esterification reaction; solvent = methanol. related phrases: Alcoholysis, aminolysis.
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Calculate the quantity of 0.01M aq NaOH needed to neutralize the HCl produced by complete solvolysis of the t-BuCl in 10ml of 0.2M t-BuCl in acetone.
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Answer:
the conversion factor is f= 6 mol of glucose/ mol of CO2
Explanation:
First we need to balance the equation:
C6H12O6(s) + O2(g) → CO2(g) + H2O(l) (unbalanced)
C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(l) (balanced)
the conversion factor that allows to calculate the number of moles of CO2 based on moles of glucose is:
f = stoichiometric coefficient of CO2 in balanced reaction / stoichiometric coefficient of glucose in balanced reaction
f = 6 moles of CO2 / 1 mol of glucose = 6 mol of glucose/ mol of CO2
f = 6 mol of CO2/ mol of glucose
for example, for 2 moles of glucose the number of moles of CO2 produced are
n CO2 = f * n gluc = 6 moles of CO2/mol of glucose * 2 moles of glucose= 12 moles of CO2
