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Kitty [74]
3 years ago
12

Which is one way that topographic maps are different from other maps?

Chemistry
2 answers:
Shtirlitz [24]3 years ago
7 0
Topographic maps contain accurate information about vertical distances, or elevations, on the Earth's surface. Other maps can show horizontal distances, etc., but not vertical distances like topographic maps.
anzhelika [568]3 years ago
5 0
One way they are different is that they show elevation
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What visual criterion is to be used to assess whether the crude reaction product is dry prior to semimicro distillation
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The visual criterion which has to be assessed  is to ensure it's not oily or sticky.

<h3>What is Distillation?</h3>

This is a separation technique that involves the use selective boiling and condensation to separate a liquid mixture into different components.

In the case of Crude reaction product , it is best to ensure that it is not oily or sticky before semimicro distillation is done.

Read more about Distillation here brainly.com/question/552187

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2 years ago
Hey man forgets that he said his coffee cup on the top of his car he starts to drive in the coffee cup rolls off the car onto th
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It would move due to it not being<span> the same speed and in the same direction so it is acted upon by an unbalanced force.</span>
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3 years ago
Balance this equation. C(s)+H2(g) -&gt; CH4(g)
Oduvanchick [21]
C (s) + 2 H2 (g) = CH4 (g)
3 0
3 years ago
The space race was between
Leviafan [203]

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the United States and the Soviet Union.

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4 0
2 years ago
What is the final temperature of the solution formed when 1.52 g of NaOH is added to 35.5 g of water at 20.1 °C in a calorimeter
Inessa [10]

Answer : The final temperature of the solution in the calorimeter is, 31.0^oC

Explanation :

First we have to calculate the heat produced.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy change = -44.5 kJ/mol

q = heat released = ?

m = mass of NaOH = 1.52 g

Molar mass of NaOH = 40 g/mol

\text{Moles of }NaOH=\frac{\text{Mass of }NaOH}{\text{Molar mass of }NaOH}=\frac{1.52g}{40g/mole}=0.038mole

Now put all the given values in the above formula, we get:

44.5kJ/mol=\frac{q}{0.038mol}

q=1.691kJ

Now we have to calculate the final temperature of solution in the calorimeter.

q=m\times c\times (T_2-T_1)

where,

q = heat produced = 1.691 kJ = 1691 J

m = mass of solution = 1.52 + 35.5 = 37.02 g

c = specific heat capacity of water = 4.18J/g^oC

T_1 = initial temperature = 20.1^oC

T_2 = final temperature = ?

Now put all the given values in the above formula, we get:

1691J=37.02g\times 4.18J/g^oC\times (T_2-20.1)

T_2=31.0^oC

Thus, the final temperature of the solution in the calorimeter is, 31.0^oC

4 0
3 years ago
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