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Elodia [21]
3 years ago
6

Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional

questions. Free Weights and Machines What are some things to consider when deciding to use free weights or machine weights?
Physics
2 answers:
kari74 [83]3 years ago
8 0

Answer:

They also simulate real-life lifting situations and promote whole-body stabilization. Free weights are generally safe when used with the proper technique. But it may take some practice to get used to lifting with free weights, and it's essential to use proper technique.

Explanation:

i did it on edg and got 100%

MAVERICK [17]3 years ago
6 0

Answer:

To confirm, the person above is correct.

Explanation:

thx homie

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I don’t know why it glitches like that???? I need help tho...brainliest for best answer
lara31 [8.8K]

Answer:

B. They each contain the same amount of matter.

Explanation:

Scientifically, mass is the amount of matter in an object.

A. Whether an object is big or small does not mean that it will be a certain mass. If you have two objects that are the same size, the denser object will have more mass, and the less dense object will have less mass.

C. The amount of space an object takes up is called the volume.

D. Different combinations and amounts of elements can give you the same mass. Rocks, books and cans of soda are made of different things.

8 0
3 years ago
How is wavelength related to a waves energy?
andreyandreev [35.5K]

Answer:

The energy of a wave is directly proportional to its frequency, but inversely proportional to its wavelength. In other words, the greater the energy, the larger the frequency and the shorter (smaller) the wavelength.

Explanation:

i hope it will help u buddy✅

8 0
3 years ago
Read 2 more answers
Two small plastic spheres are given positive electrical charges. When they are a distance of 14.8cm apart, the repulsive force b
sdas [7]

Answer:

Explanation:

Case I: They have same charge.

Charge on each sphere = q

Distance between them, d = 14.8 cm = 0.148 m

Repulsive force, F = 0.235 N

Use Coulomb's law in electrostatics

F=\frac{Kq_{1}q_{2}}{d^{2}}

By substituting the values

0.235=\frac{9\times10^{9}q^{2}}{0.148^{2}}

q=7.56\times10^{-7}C

Thus, the charge on each sphere is q=7.56\times10^{-7}C.

Case II:

Charge on first sphere = 4q

Charge on second sphere = q

distance between them, d = 0.148 m

Force between them, F = 0.235 N

Use Coulomb's law in electrostatics

F=\frac{Kq_{1}q_{2}}{d^{2}}

By substituting the values

0.235=\frac{9\times 10^{9}\times 4q^{2}}{0.148^{2}}

q=3.78\times10^{-7}C

Thus, the charge on second sphere is q=3.78\times10^{-7}C and the charge on first sphere is 4q = 4\times 3.78\times 10^{-7}=1.51 \times 10^{-6} C.

6 0
4 years ago
it is possible to tell if objects in space are moving closer to us or farther away based on which of the following?
valkas [14]
I think you forgot to give the options along with the question. I am answering the question based on my knowledge and research. It is <span>possible to tell if objects in space are moving closer to us or farther away based on several procedures like parallax and standard candles. I hope the answer has come to your help.</span>
7 0
4 years ago
Read 2 more answers
(50 POINT REWARD) PHYSICS, IMAGE IS ATTACHED BELOW (TRIG/VECTORS)
daser333 [38]

Answer:

Explanation:

The east vector is 10cos45 = 7.07 km

The north vector is 10sin45 - 10 = -2.93 km

The displacement magnitude is

d = √(7.07² + 2.93²) = 7.65... = 8 km

θ = arctan(-2.93/7.07) = -22.51... = 23° south of east.

6 0
3 years ago
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