If the trail is 10 miles 1/2 of that is 5. Jayden posted up three signs so to find out the distance between the second and third sign you would divide 5 by 3 (5 ÷ 3.) The answer you would get would be 3 1/3 apart in distance
Answer:
Well from all the exams and assignments I've had, 100 points is the full grade so losing 100 points would mean you would fail with a 0
Answer: B. x = 16/3
3/5x + 1/2 = 3/4x -3/10
minus 3/4x on both sides
-3/20x + 1/2 = -3/10
minus 1/2 on both sides
-3/20x = -3/10
multiply both sides by 20/-3
x = 16/3
The surface area of the triangular prism is 144 cm²
<u>Explanation:</u>
Given:
Base of the triangle = 4
Height of the triangle = 3
Hypotenuse of the triangle = 5
Length of the prism = 11
Surface area of the rectangular prism = ?
Surface area, A = ![ah + bh + ch + \frac{1}{2} \sqrt{-a^4+2(ab)^2 + 2(ac)^2-b^4 + 2(bc)^2 - c^4}](https://tex.z-dn.net/?f=ah%20%2B%20bh%20%2B%20ch%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%5Csqrt%7B-a%5E4%2B2%28ab%29%5E2%20%2B%202%28ac%29%5E2-b%5E4%20%2B%202%28bc%29%5E2%20-%20c%5E4%7D)
On substituting the value, we get:
![A = 4 X 11 + 3 X 11 + 5 X 11+\frac{1}{2} \sqrt{-(4)^4 + 2(4X3)^2+2(4X5)^2-3^4 + 2(3X5)^2 - 5^4} \\\\A = 144 cm^2](https://tex.z-dn.net/?f=A%20%3D%204%20X%2011%20%2B%203%20X%2011%20%2B%205%20X%2011%2B%5Cfrac%7B1%7D%7B2%7D%20%5Csqrt%7B-%284%29%5E4%20%2B%202%284X3%29%5E2%2B2%284X5%29%5E2-3%5E4%20%2B%202%283X5%29%5E2%20-%205%5E4%7D%20%5C%5C%5C%5CA%20%3D%20144%20cm%5E2)
Therefore, the surface area of the triangular prism is 144 cm²
Answer:
98,123
Step-by-step explanation: