The object is maintaining a constant velocity
Given: Initial velocity of toy car (u ) = 0
Final velocity of toy car (v) = 0.12 m/s
Required time (t) = 0.1 s
To find: The acceleration of the toy car.
Let the acceleration of the toy car be (a)
Formula Used: 1st kinematic equation of motion
v = u + at ---------------------------(i)
Here, all alphabets are in their usual meanings
Now, from equation (i), we shall calculate the value of 'a'.
so, a = (v - u) /t
or, a = (0.12 m/s - 0) / 0.1s
or, a = 1.2 m/s²
Hence, the required acceleration of the toy car will be 1.2 m/s².
Answer:
336.9520 atm
Explanation:
The Gas Equation is as follows;-
Pressure×Volume=Number of Moles × Universal Gas Constant ×Temperature(in Kelvin)
Given Parameters
Number of moles-0.614 mol
Temperature 12°C or 12+273.15 ie 285.15°F
Volume-4.32 L
Universal Gas Constant-8.314 J/mol·K
Pressure -?(in atm)
Plugging in all the values in the Gas Equation:-
Pressure=
Pressure=336.9520 atm
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Answer:
a) The final pressure is 1.68 atm.
b) The work done by the gas is 305.3 J.
Explanation:
a) The final pressure of an isothermal expansion is given by:

Where:
: is the initial pressure = 5.79 atm
: is the final pressure =?
: is the initial volume = 420 cm³
: is the final volume = 1450 cm³
n: is the number of moles of the gas
R: is the gas constant
Hence, the final pressure is 1.68 atm.
b) The work done by the isothermal expansion is:

Therefore, the work done by the gas is 305.3 J.
I hope it helps you!