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Oksana_A [137]
3 years ago
7

A 5.5 kg box is pushed across the lunch table. The acceleration of the box is 4.2 m/s2. What was the net force applied to the bo

x?
Physics
2 answers:
Reptile [31]3 years ago
6 0

23.1N of force applied


Bezzdna [24]3 years ago
5 0
Use this numbers that you are given and plug them into the formule for net force

Net force= m*a (mass times acceleration)

Therefore the net force is equal to (5.5 kg)*(4.2 m/s^2)= 23.1 N

Answer: Net force= 23.1 N
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