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algol [13]
1 year ago
12

Which has the highest heat capacity? (values of heat capacities and calculations are unnecessary).

Physics
1 answer:
KATRIN_1 [288]1 year ago
5 0

Water has the maximum specific heat capacity of any fluid.

The amount of heat that one gram of a material needs either absorb or lose in order to alter its temperature by a degree Celsius is known as specific heat. This equates to one caloric, or 4.184 Joules, for water.

<h3>High heat capacity: what is it?</h3>
  • Consider the amount of time it takes for a pot to get warm to the touch on the stove as opposed to how long it takes for the water within to warm up.
  • A substance with a high heat capacity may absorb a lot of heat before registering a change in temperature.
<h3>Why does water have the greatest ability to retain heat?</h3>

Although the hydrogen bonds in water are much too weak to be compared to intra - molecular bonds like covalently or ionic bonds, they are nevertheless strong enough to require a lot of energy to break. Water boils at 100°C for this reason.

Many people believe hydrogen bonding is the cause of water's high specific heat.

learn more about heat capacity here

brainly.com/question/26866234

SPJ4

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Answer: 2.27\ m/s^2

Explanation:

Given

Length of the race track L=200\ m

the radius of curvature of the track r=29.5\ m

time taken to run on track is t=24.4\ s

Speed of runner is

\Rightarrow v=\dfrac{L}{t}=\dfrac{200}{24.4}\\\\\Rightarrow v=8.196\ m/s

Centripetal acceleration is

\Rightarrow a_c=\dfrac{v^2}{r}=\dfrac{8.196^2}{29.5}\\\\\Rightarrow a_c=2.27\ m/s^2

5 0
3 years ago
A rigid rectangular loop, which measures 0.30 m by 0.40 m, carries a current of 5.5 A, as shown in the figure. A uniform externa
slamgirl [31]

Answer:

The magnitude will be "(1.097 \ N/m)\hat{j}". The further explanation is given below.

Explanation:

Trying to determine what is usual for a rectangular loop plane,

⇒  \hat{n}=(Cos35^{\circ})(-\hat{i})+(Sin35^{\circ})(\hat{k})

Magnetic moment is given as:

μ = IA\hat{n}

On putting the values in the above formula, we get

μ = (5.5A)[(0.3m)(0.4m)][(Cos35^{\circ})(\hat{i})+(Sin35^{\circ})(-\hat{k})]

  = 0.66 Am^2[(Cos35^{\circ})(\hat{i})+(Sin35^{\circ})(\hat{k})]

Now the external vector-shaped torque seems to be:

Magnitude,

\sigma=\hat{\mu}\times\hat{\beta}

On putting the values in the above formula, we get

⇒ \sigma=[(0.06Am^2)(Cos35^{\circ}(-\hat{i})+Sin35^{\circ}(-\hat{k})]\times (2.9T)(-\hat{i})

⇒    = (0.66)(2.9)Cos35^{\circ}(\hat{i}\times \hat{i})+(0.66)(2.9)Sin35^{\circ}(\hat{k}\times \hat{k})

⇒    = 0+(1.97 \ N/m)\hat{j}

⇒    =(1.097 \ N/m)\hat{j}

8 0
3 years ago
a stone of mass 750 kg is thrown vertically upward with a velocity of 10m/s find the potential energy at the greatest height and
Taya2010 [7]

Answer:

Potential Energy at the greatest point = 37.5 J

Explanation:

Given :

Mass is 750 g

In term of kg :

Mass is 0.75 kg .

Velocity ( v ) = 10 m / sec

We have formula for kinetic energy :

K.E. = 1 / 2 m v²

Putting values now :

K.E. = 1 / 2 × 0.75 × 10 × 10

K.E. = 1 / 2 × 75 J

K.E. = 37.5 J

Since K.E . = P.E.

Thus potential energy of stone is 37.5 J .

8 0
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3 years ago
What is the Range of the projectile motion?
never [62]

Answer:

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hope you're looking for this.

4 0
3 years ago
Read 2 more answers
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