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STatiana [176]
3 years ago
7

An object has density rho.

Physics
1 answer:
tatyana61 [14]3 years ago
4 0

Answer:

a. the density will not change

b. D' = 0.125 D

So, the density will change by a factor of 0.125

Explanation:

a.

Density is the material property and the value of density is constant for all solid materials. So, when the dimensions of the a solid are increased, while the material is same, then the material must be added to the object for increasing its dimensions. So, with the increase in the volume, the mass of the object also increases. And as a result the density of the object remains constant.

Since, here the material remains the same.

<u>Therefore, the density will not change</u>

<u></u>

b.

Density = mass/Volume

D = m/V   ------------ equation (1)

Now,

V = LWH   ----------- equation (2)

Now, if each dimension increases by a factor of 2, the volume becomes:

V' = (2L)(2W)(2H)

V' = 8 LWH

using equation (2)

V' = 8 V

So, for constant mass, density becomes:

D' = m/V'

D' = m/8V

using equation (1)

D' = D/8

<u>D' = 0.125 D</u>

<u>So, the density will change by a factor of 0.125</u>

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Explanation:

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Helge, Steve, and Heidi are sitting on a sled on a slope covered with a hard snow. The sled is stationary. The friends have diff
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3 years ago
Physics !!!!!!!!!!!!!!!!!
madreJ [45]

Answer:

1) v = -0.89 m/s

2) v = 36.5 m/s

Explanation:

1) Given

The mass of the boy, M = 45 Kg

The mass of the skateboard, m = 2 Kg

The initial velocity of the boy and skateboard is zero

According to the law of conservation of linear momentum

                              MV + mv = 0

                                           V = - mv/M

Substituting the given values in the above equation

                                          V = -2 x 20/ 45

                                             = -0.89 m/s

Hence, the velocity of the boy, v = -0.89 m/s

2) Given

The mass of the boy, M = 47 Kg

The mass of the skateboard, m = 8 Kg

The initial combined velocity of the boy and skateboard, u = 4.2 m/s

The boy jumped off from the skateboard with velocity, V = -1.3 m/s

According to the law of conservation of momentum,

                      MV + mv = (M + m)u

                                    v = [(M + m)u - MV] / m

Substituting the given values,

                                     v = [(47 + 8)4.2 - 47(-1.3)] / 8

                                        = 36.5 m/s

Hence, the velocity of the skateboard, v = 36.5 m/s

3 0
4 years ago
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