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Citrus2011 [14]
2 years ago
12

4. Some early mornings , dew drops can be found on grass or a car parked outside,

Physics
1 answer:
horsena [70]2 years ago
3 0

In some early mornings , dew drops can be found on grass or a car parked outside, but not on other materials such as the sidewalk because  the night -time temperature on grass and the car went below the dew point, but  the temperature of the concrete did not drop enough to reach the dew point  level

Dew can be formed on any object when the temperature of the object drop. When this happen, the object will be cool which will eventually cool the surrounding air around the object.

Dew drops is as a result of condensation in the air. When the cool air causes the air vapor to convert to liquid. The dew will form when the temperature of the object balances with the dew point in the surrounding environment.

In some early mornings , dew drops can be found on grass or a car parked outside, but not on other materials such as the sidewalk because  the night -time temperature on grass and the car went below the dew point, but  the temperature of the concrete did not drop enough to reach the dew point  level

Therefore the correct option is therefore A

Learn more here : brainly.com/question/13834972

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100 points
luda_lava [24]

Answer:

10.21m/s²

Explanation:

Radial acceleration, also known as centripetal acceleration, refers to the acceleration of an object along the circular radius. It can be calculated using the formula:

a(r) = v²/r

Where a(r) = radial acceleration

v = velocity

r = radius of the circular path

According to the information provided in the question, velocity (v) = 17.5m/s, radius = 30m. Hence;

a(r) = v²/r

a(r) = 17.5²/30

a(r) = 10.208333

a(r) = 10.21m/s²

5 0
3 years ago
A skier leaves the end of a horizontal ski jump at 23.0 m/s and falls through a vertical distance of 3.45 m before landing.
Len [333]

Explanation:

Given

Velocity v = 23.0m/s

Distance S = 3.45m

Required

Time it will take the skier to reach the ground;

Using the equation of motion;

S = ut + 1/2gt²

3.45 = 23t + 1/2(9.8)t²

3.45 = 23t + 4.9t²

4.9t²+23t-3.45 = 0

Factorize;

t = -23 ±√23²-4(4.9)(-3.45)/2(4.9)

t = -23 ±√529+67.62/9.8

t = -23±√596.62/9.8

t = -23±24.43/9.8

t = 1.43/9.8

t = 0.146 secs

Hence take the skier 0.146 secs to reach the ground.

b) Horizontal distance covered is the range;

Range = U√2H/g

Range = 23√2(3.45)/9.8

Range = 23√6.9/9.8

Range = 23√0.7041

Range = 23(0.8391)

Range = 19.29m

Hence the horizontal distance travelled in air is 19.29m

7 0
2 years ago
Anyone! Help me! (:o
Gnom [1K]
You have written the answer within your question.


mass of 1kg metal is "1 kilogram"

but when you talk about it's weight
then,
it's weight is 9.8 Newton.
5 0
3 years ago
Read 2 more answers
What total distance will a sound wave travel in air in 3.00 seconds at stp?
dimaraw [331]
At stp conditions (T=0^{\circ}C), the speed of sound is
v=331.2 m/s
The sound wave moves by uniform motion, so we can use the basic relationship between space, time and velocity:
S=vt
where S is the distance covered by the sound wave in a time t. In our problem, t=3.00 s, therefore the distance covered by the sound wave is
S=vt=(331.2 m/s)(3.00 s)=993.6 m
4 0
3 years ago
What is the gravitational potential energy of a 2.5kg object that is 300m above the surface of the earth? g=10m/s
Alexus [3.1K]

Answer:

7350 J

Explanation:

Gravitational Potential Energy: This is defined as the energy possessed by a body due to it's position in the gravitational field. The S.I unit is Joules(J).

Applying,

E.p = mgh..................... Equation 1

Where E.p = Gravitational potential Energy, m = mass of the object, h = height of the object above the surface of the earth, g = acceleration due to gravity.

Given: m = 2.5 kg, h = 300 m

Constant: g = 9.8 m/s²

Substitute these values into equation 1

E.p = 2.5(300)(9.8)

E.p = 7350 J.

4 0
3 years ago
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