Answer:
78.156 m/s
Explanation:
(assuming no upthrust from the air on the arrow)
Ball has a motion only under ther gravity
Apply motion equation upwards
(g = 10m/s²)
V² = U² + 2as
= 82.5² + 2*(-10)*(36.3-1.41.)
= 6108.45
V = 78.156 m/s
<h2>
Answer:5
![ms^{-1}](https://tex.z-dn.net/?f=ms%5E%7B-1%7D)
,133.6
![m](https://tex.z-dn.net/?f=m)
,51.18
![ms^{-1}](https://tex.z-dn.net/?f=ms%5E%7B-1%7D)
</h2>
Explanation:
Let
,
be the horizontal and vertical components of velocity.
Question a:
Horizontal component of velocity is the ratio of range and time of flight.
So,horizontal component of velocity is ![\frac{235}{47}=5ms^{-1}](https://tex.z-dn.net/?f=%5Cfrac%7B235%7D%7B47%7D%3D5ms%5E%7B-1%7D)
So,![v_{x}=5ms^{-1}](https://tex.z-dn.net/?f=v_%7Bx%7D%3D5ms%5E%7B-1%7D)
Question b:
Time of flight=![\frac{2v_{y}}{g}](https://tex.z-dn.net/?f=%5Cfrac%7B2v_%7By%7D%7D%7Bg%7D)
So,![v_{y}=\frac{47\times 9.8}{2}=51.18ms^{-1}](https://tex.z-dn.net/?f=v_%7By%7D%3D%5Cfrac%7B47%5Ctimes%209.8%7D%7B2%7D%3D51.18ms%5E%7B-1%7D)
Maximum height is given by ![\frac{v_{y}^{2}}{2g}](https://tex.z-dn.net/?f=%5Cfrac%7Bv_%7By%7D%5E%7B2%7D%7D%7B2g%7D)
So,maximum height is ![\frac{51.18^{2}}{2\times 9.8}=133.6m](https://tex.z-dn.net/?f=%5Cfrac%7B51.18%5E%7B2%7D%7D%7B2%5Ctimes%209.8%7D%3D133.6m)
Question c:
The vertical velocity is already calculated in Question b.
![v_{y}=51.18ms^{-1}](https://tex.z-dn.net/?f=v_%7By%7D%3D51.18ms%5E%7B-1%7D)
Answer:
D. The acceleration is downward at all points in the motion
Explanation:
:D
The answer is Phenotype.
Phenotype is the observable traits on the organism which are mainly influenced by how the genotype of the organism interacts with the environment. An example of how phenotype is determined is when a gene has several alleles. The dominant alleles are expressed in phenotype while the recessive one is masked. Epistasis of alleles also occurs in many other cases.