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melomori [17]
3 years ago
5

When hiking at altitude, the air pressure drops to 825,000Pa. Solve the force that site exerts against the side of a rectangular

tent wall having dimensions of 2.00m long and 0.750m wife.
Physics
1 answer:
OLga [1]3 years ago
7 0

Answer:

The force is 1237500N

Explanation:

We can apply the following expression

pressure=\frac{Force}{Area}

To find the area of rectangular tent wall:

Area=length *width\\Area=2.00m*0.750m\\Area=1.5m^{2}

Now to find the force:

pressure=825,000pa

pressure=\frac{Force}{Area}

Force=pressure*Area\\Force=825000pa*1.5m^{2} \\Force=1237500N

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Having this clear, let's find t from (1):  

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Rewritting (2):

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This is a quadratic equation (also called equation of the second degree) of the form at^{2}+bt+c=0, which can be solved with the following formula:

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Solving (5) we find the positive result is:

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