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2 years ago

How does a wind turbine transform mechanical energy into electrical energy?

Physics

1 answer:

Alex777 [14]2 years ago

4 0

Answer:

"A turbine takes the kinetic energy of a moving fluid, air in this case, and converts it to a rotary motion. As wind moves past the blades of a wind turbine, it moves or rotates the blades. These blades turn a generator."

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How does the tide cycle affect erosion along a sea coast?

Readme [11.4K]

<span>The tides are a constant pulling and pushing against the land. Causing erosion.</span>

4 0

2 years ago

A radar receiver indicates that a pulse return as an echo in 20 μs after it was sent. How far away is the reflecting object? (c

Assoli18 [71]

A radar receiver indicates that a pulse return as an echo in 20 μs after it was sent. The reflecting object would be 3000 m away .

Phenomenon of hearing back our own sound is called an echo. It is due to successive reflection of sound waves from the surfaces or obstacles of large size. To hear an echo, there must be a time gap of 0.1 second in original sound and the reflected sound.

Given

time = 20 μs = 20 * $10^{-6}$ s

let distance to the reflecting surface be = x

total distance travelled by pulse will be = 2x

speed = 3.0 × $10^{8}$ m/s

distance = speed * time

2x = 3.0 × $10^{8}$ * 20 * $10^{-6}$

x = 3000 m

The reflecting object would be 3000 m away

To learn more about echo here

brainly.com/question/14861578?referrer=searchResults

#SPJ4

5 0

1 year ago

A book rests on a wooden table is an example of

kykrilka [37]

Answer:

Static friction

Explanation:

When there is contact between two surfaces and there is no movement, there is static friction. So, if we have a book that rests on a wooden table, we have an example of Static friction, where this force avoids the movement of the book.

7 0

10 months ago

A fin whale is swimming at the speed of 35 km/h how many hours will it take to swim 7 km

Aleks04 [339]

Answer:

0.2 hours

Explanation:

$\frac{7}{35} = 0.2$

7 0

2 years ago

Singing that is off-pitch by more than about 1% sounds bad. How fast would a singer have to be moving relative to the rest of a

Nina [5.8K]

Answer:

-3.396 m/s or 3.465 m/s

Explanation:

v = Speed of sound in air = 343 m/s

$v_s$ = Relative speed of the singer

f = Observed frequency

f' = Actual frequency

1% change can mean $f=1.01f'$

From the Doppler effect equation we have

$f=f'\dfrac{v}{v+v_s}\\\Rightarrow 1.01f'=f'\dfrac{v}{v+v_s}\\\Rightarrow 1.01=\dfrac{343}{343+v_s}\\\Rightarrow v_s=\dfrac{343}{1.01}-343\\\Rightarrow v_s=-3.396\ m/s$

The velocity is -3.396 m/s

when $f=0.99f'$

$f=f'\dfrac{v}{v+v_s}\\\Rightarrow 0.99f'=f'\dfrac{v}{v+v_s}\\\Rightarrow 0.99=\dfrac{343}{343+v_s}\\\Rightarrow v_s=\dfrac{343}{0.99}-343\\\Rightarrow v_s=3.46464646465\ m/s$

The velocity is 3.465 m/s

3 0

2 years ago