Question

What is the simplified form of 2 over x squared plus x minus 1 over x ?

Answer 1

Answer:

$\boxed{\boxed{\dfrac{2}{x^2+x}-\dfrac{1}{x}=\dfrac{1-x}{x(x+1)}}}$

Step-by-step explanation:

The given expression is,

$\dfrac{2}{x^2+x}-\dfrac{1}{x}$

Factoring $x^2+x$,

$x^2+x=x(x+1)$

Hence,

$=\dfrac{2}{x(x+1)}-\dfrac{1}{x}$

$\mathrm{Least\:Common\:Multiplier\:of\:}x\left(x+1\right),x = x\left(x+1\right)$

So,

$=\dfrac{2-(x+1)}{x(x+1)}$

$=\dfrac{2-x-1}{x(x+1)}$

$=\dfrac{1-x}{x(x+1)}$

Answer 2

I hope this helps you