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liberstina [14]
3 years ago
12

If a 2.0Ω resistor and a 4.0Ω resistor are connected with a 12 volt battery, what is the total resistance of the circuit?

Physics
1 answer:
makvit [3.9K]3 years ago
3 0

answer:

6 ohms

Explanation:

if these two resistors are connected in series, the total resistance is the sum: 2+4 = 6 (ohms)

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Linearly polarized light whose Jones vector is [0 1] (horizontally polarized) is sent through a train of two linear polarizers.
ivann1987 [24]

Answer:

Following are the solution to the given question:

Explanation:

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8 0
2 years ago
Given Vout = 17.33 vpp and R1 = 3 kΩ, find the value of RF required to provide Av = 4.33. (Round your answer to 2 decimal places
Olenka [21]

Answer:

The magnitude of V_{2} is 4 V and phase of input voltage is zero

Explanation:

Given:

Output voltage V_{out} = 17.33

Resistance R_{1} = 3 kΩ

Voltage gain A_{v} = 4.33

For finding feedback resistance we use gain equation

Gain equation for non inverting op-amp is given by,

     A_{v} = 1+\frac{R_{f} }{R_{1} }

   4.33 = 1+ \frac{R_{f} }{3 k }

     R_{f} ≅ 10 kΩ

For finding input voltage we use,

   A_{v} = \frac{V_{out} }{V_{2} }

    V_{2} = \frac{17.33}{4.33}

    V_{2} = 4 V

The Phase of V_{2} is zero because output voltage phase is 360°

Therefore, the magnitude of V_{2} is 4 V and phase of input voltage is zero

7 0
3 years ago
In a certain region of space, a uniform electric field has a magnitude of 4.30 x 104 n/c and points in the positive x direction.
denis23 [38]
The magnetic force exerted by a field E to a charge q is given by F=Eq. In this case, F=4.30*10^4*(6.80mu C). 1mu C=10^-6C, so F=4.30*6.80=10^-2=0.29N. The direction is in the x direction, the direction that the field is applied because the charge is positive.
5 0
3 years ago
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