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2 years ago

BRAINLIST HELP

Mathematics

2 answers:

tigry1 [53]2 years ago

8 0

The answer is 50 because I trusted my gut with this one

Gala2k [10]2 years ago

3 0

Answer:

The second one.

Step-by-step explanation:

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70=p so what number is p?

nirvana33 [79]

70 equals p so p is 70

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3 years ago

Read 2 more answers

This table shows some values of an exponential function. what is the function

Yuri [45]

Answer:

there is no table so we are therefore unable to answer this question

Step-by-step explanation:

sorry

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3 years ago

A number is chosen at random from 1 to 25. Find the probability of selecting an even number that is greater than 13.

mamaluj [8]

Answer:

14 16,18,20 22,24

so, 6 out of 24

6/24 simplifies to 1/4

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3 years ago

A TV has a listed price of $695.95 before tax. If the sales tax rate is 7.75%, find the total cost of the TV with sales tax incl

vivado [14]

Answer:

7.75%/100×695.95=53.93

695.95+53.93=749.88

answer:749.90

6 0

3 years ago

The average weight of a newborn panda is 0.2, or 2/10 pound. Between what two integers is the weight of a newborn panda?

sweet-ann [11.9K]

Answer:

$\frac{2}{10}$ lies between 0 and 1.

Step-by-step explanation:

We must have in mind that given average weight of a newborn panda is a non-integer rational number, such that lies between two integer rational number. In other words, this number must satisfy the following condition:

$n < \frac{a}{b} < n +1$ , $n, a, b \in \mathbb{N}_{O}$

$\mathbb{N}_{O} = \mathbb{N}\,\cup\,{\{0\}}$

Which is now developed mathematically to deduce a useful expression to find integers:

1) $n < \frac{a}{b} < n +1$ Given

2) $n \cdot 1 < \frac{a}{b} < n\cdot 1 + 1$ Modulative property

3) $n \cdot (b\cdot b^{-1}) < a\cdot b^{-1} < n \cdot (b\cdot b^{-1}) + b\cdot b^{-1}$ Existence of Multiplicative inverse/Definition of division.

4) $(n\cdot b)\cdot b^{-1} < a\cdot b^{-1}< [(n+1)\cdot b] \cdot b^{-1}$ Commutative, Associative and Distributive properties.

5) $n\cdot b < a < (n+1)\cdot b$ Compatibility with Multiplication/Existence of Multiplicative Inverse/Modulative Property/Result.

If we know that $a = 2$ and $b = 10$ , the following inequation is formed:

$10\cdot n < 2 < 10\cdot (n+1)$

It is quite evident to conclude that $\frac{2}{10}$ lies between 0 and 1.

6 0

3 years ago