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otez555 [7]
3 years ago
6

A spherical balloon is 40 ft in diameter and surrounded by air at 60°F and 29.92 in Hg abs.(a) If the balloon is filled with hyd

rogen at a temperature of 70°F and atmospheric pressure, what total load can it lift? (b) If it contains helium instead of hydrogen, other conditions remaining the same, what load can it lift? Answers (a) 2381 lb; (b) 2209 lb
Physics
2 answers:
azamat3 years ago
5 0
For the answer to the questions above, I'll give the formulas so that you can answer the equation easily.

These are the equations you need to solve this: 

<span>Lift Load = Buoyancy Force = (Weight of air inside balloon if it were filled with outside dry air) - (Weight of actual gas inside balloon) </span>

<span>Weight of gas inside balloon = (density of gas) (acceleration of gravity at earth's surface) (balloon volume) </span>

<span>Density of gas = (absolute pressure)(Molecular Weight of Gas) / [(Specific Gas Constant)(absolute temperature)] </span>

<span>Balloon Volume = (4/3) π (balloon radius)^3 
</span>
All you have to do is substitute them with the values.
masha68 [24]3 years ago
3 0
It's obviously b because the more helium it has, the lighter it is...
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The field is

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R is the radius of the spherical shell.

Notice that the field is exactly the same as the field due to a point-charge
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4 years ago
A toy car attached to a rope is traveling around in a circle. It makes 4 laps in 12s.What is the angular velocity of the toy car
umka21 [38]

Answer:

2.09 rad/s

Explanation:

Given that,

A toy car makes 4 laps in 12 s.

We need to find the angular velocity of the toy car. We need to find the angular velocity of the toy car.

4 laps = 25.13 rad

So,

v=\dfrac{25.13\ rad}{12\ s}\\\\v=2.09\ rad/s

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3 0
3 years ago
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6 0
3 years ago
HELP PLZ! A parachutist jumps out of an aeroplane and accelerates uniformly at 9.8 ms-2 for ten seconds. a. How far does she tra
Mrac [35]

Answer:

a.) 490m

b.) 98m/s

Explanation:

Given that the

Acceleration g = 9.8 m/s^2

Time = 10s

Since the parachutist jumps out of an aeroplane. The parachutist jumped out from rest. Initial velocity U is therefore equal to zero. That is,

U = 0

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The height can be calculated by using second equation of motion

H = Ut + 1/2gt^2

Substitute g and t into the formula

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Substitute g and H into the formula.

Remember that U = 0

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V = 98 m/s

Therefore, her final velocity is 98 m/s

4 0
3 years ago
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