Answer:
The average atomic mass of element X is 17.561 u.
Explanation:
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
We are given:
Mass of isotope X-17 = 17 u
Percentage abundance of isotope X-17 = 65.20 %
Fractional abundance of isotope 1 = 0.6520
Mass of isotope X-18 = 18 u
Percentage abundance of isotope X-18 = 13.50 %
Fractional abundance of isotope X-18 = 0.1350
Mass of isotope X-19 = 19 u
Percentage abundance of isotope X-19 =21.30%
Fractional abundance of isotope X-19 = 0.2130
Putting values in equation 1, we get:
![\text{Average atomic mass of Z}=\sum[(17 u\times0.6520 )+(18 u\times 0.1350)+(19 u\times 0.2130)]](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20atomic%20mass%20of%20Z%7D%3D%5Csum%5B%2817%20u%5Ctimes0.6520%20%29%2B%2818%20u%5Ctimes%200.1350%29%2B%2819%20u%5Ctimes%200.2130%29%5D)
Answer:
A, The water moving away
Explanation:
When the pebble hits the water the surface tension breaks causing the water to separate away and make a ripple in the water.
Answer:
The average force ≅ 519.44 N.
Explanation:
Impulse = change in momentum of a body
i.e Ft = m(v - u)
where F is the force, t is the time, m is the mass of the body, v is the final velocity and u is the initial velocity.
m = 55.0 g (0.055 Kg), t = 0.00360 s, v = 34.0 m/s, since the ball was initially at rest; u = 0 m/s
So that,
F x 0.00360 = 0.055(34 - 0)
F x 0.00360 = 0.055 x 34
= 1.87
F = 
= 519.4444
The average force exerted on the ball by the club is approximately 519.44 N.
Geologists do not use a minerals color or streak to identify them because some minerals can have the same streak and color but the correct answer is
b) color
Answer:
12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.
Explanation:
In the United States, a standard "drink" of beer has 12 ounces, a standard "drink" of wine has 5 ounces and standard drink of liquor has 1.5 ounces. Then, we obtain the quantity of drinks by dividing the total volume of each drink by its respective unit volume and summing each term. That is:
12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.
