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3 years ago

15

A car that brakes suddenly comes to a screeching halt. Is the sound energy produced in this conversion a useful form of energy?

Yes or No------ Then explain why or why not. This is due tomorrow so please help!

1 answer:

Nezavi [6.7K]3 years ago

7 0

Answer:

No, the sound produced by screeching brakes is not a useful form of energy, because it does not contribute to stopping the car.

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The electrical resistance of a wire varies directly as its length and inversely as the square of its diameter. a wire with a len

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The length of the wire in the problem is changed from 200 inches to 500 inches, so the new length is 2.5 times the initial length:
$\frac{L_1}{L_0}= \frac{500}{200}=2.5$
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4 years ago

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1 year ago

A neutron star has a mass of 2.0 × 1030 kg (about the mass of our sun) and a radius of 5.0 × 103 m (about the height of a good-s

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Answer:

$v=516526.9m/s$

Explanation:

The force to which the object of mass <em>m</em> is attracted to a star of mass <em>M</em> while being at a distance <em>r</em> is:

$F=\frac{GMm}{r^2}$

Where $G=6.67\times10^{-11}Nm^2/Kg^2$ is the gravitational constant.

Also, Newton's 2nd Law tells us that this object subject by that force will experiment an acceleration given by <em>F=ma.</em>

We have then:

$ma=\frac{GMm}{r^2}$

Which means:

$a=\frac{GM}{r^2}$

The object departs from rest ( $v_0=0m/s$ ) and travels a distance <em>d</em>, under an acceleration <em>a</em>, we can calculate its final velocity with the formula $v^2=v_0^2+2ad$ , which for our case will be:

$v^2=2ad=\frac{2GMd}{r^2}$

$v=\sqrt{\frac{2GMd}{r^2}}$

We assume <em>a</em> constant on the vecinity of the surface because d=0.025m is nothing compared with $r=5\times10^3m$ . With our values then we have:

$v=\sqrt{\frac{2GMd}{r^2}}=\sqrt{\frac{2(6.67\times10^{-11}Nm^2/Kg^2)(2\times10^{30}Kg)(0.025m)}{(5\times10^3m)^2}}=516526.9m/s$

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3 years ago