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kakasveta [241]
3 years ago
11

A line passes through the points (-4,-8) and (6,10). Write an equation that represents a line parallel to this line.

Mathematics
1 answer:
Tcecarenko [31]3 years ago
8 0

Answer:

The answer is Jksbns because it is relevant to communism and kim jong un

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Evaluate the expression 4y - 11 when y = 14
vampirchik [111]

Answer:

The answer is 45 because 4 times 14 is 56 if you subtract 11 you get 45

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Select the correct answer. which expression is equivalent to the given expression? assume the denominator does not equal zero. a
Alexxandr [17]

If the denominator does not equal 0, the equivalent expression of \frac{14x^4y^6}{7x^8y^2} is \frac{2y^{4}}{x^{4}}\frac{x^{10} y^{14}}{729}

<h3>How to determine the equivalent expression?</h3>

The expression is given as:

\frac{14x^4y^6}{7x^8y^2}

Divide 14 by 7

\frac{14x^4y^6}{7x^8y^2} = \frac{2x^4y^6}{x^8y^2}

Apply the law of indices

\frac{14x^4y^6}{7x^8y^2} = \frac{2y^{6-2}}{x^{8-4}}

Evaluate the differences in the exponents

\frac{14x^4y^6}{7x^8y^2} = \frac{2y^{4}}{x^{4}}

Hence, the equivalent expression of \frac{14x^4y^6}{7x^8y^2} is \frac{2y^{4}}{x^{4}}

Read more about equivalent expressions at:

brainly.com/question/2972832

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4 0
2 years ago
What is 200 times 40000
denis-greek [22]

200 times 40000 is 8000000.

       200

x 40000

---------------

8000000

8 0
3 years ago
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randy has 128 ounces of dog food. he feeds his dog 8 ounces of food each day. how much days will the dog food last
notsponge [240]
You do 128÷8 and you get 16
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2 years ago
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Tyler went to the supermarket to buy food for a food pantry. He has $36, and can carry up to 20 pounds of food in his backpack.
horrorfan [7]

Answer:

  • solutions: (2, 10), (4, 5)
  • non-solutions: all other points

Step-by-step explanation:

It can be useful to graph the inequalities related to Tyler's limits of money and weight.

  1x +3y ≤ 36 . . . . . . the limit on the cost of the items Tyler can afford

  1x +1.5y ≤ 20 . . . . . the limit on the weight of the items Tyler can carry

Then plotting the given points shows that only (2, 10) and (4, 5) are in the doubly-shaded area that is the solution space. The other points are not a solution.

6 0
3 years ago
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