If the denominator does not equal 0, the equivalent expression of $\frac{14x^4y^6}{7x^8y^2}$ is $\frac{2y^{4}}{x^{4}}$ $\frac{x^{10} y^{14}}{729}$

<h3>How to determine the equivalent expression?</h3>

The expression is given as:

$\frac{14x^4y^6}{7x^8y^2}$

Divide 14 by 7

$\frac{14x^4y^6}{7x^8y^2} = \frac{2x^4y^6}{x^8y^2}$

Apply the law of indices

$\frac{14x^4y^6}{7x^8y^2} = \frac{2y^{6-2}}{x^{8-4}}$

Evaluate the differences in the exponents

$\frac{14x^4y^6}{7x^8y^2} = \frac{2y^{4}}{x^{4}}$

Hence, the equivalent expression of $\frac{14x^4y^6}{7x^8y^2}$ is $\frac{2y^{4}}{x^{4}}$

Read more about equivalent expressions at:

brainly.com/question/2972832

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4 0

2 years ago

What is 200 times 40000

denis-greek [22]

200 times 40000 is 8000000.

200

x 40000

---------------

8000000

8 0

3 years ago

Read 2 more answers

randy has 128 ounces of dog food. he feeds his dog 8 ounces of food each day. how much days will the dog food last

notsponge [240]

You do 128÷8 and you get 16

5 0

2 years ago

Read 2 more answers

Tyler went to the supermarket to buy food for a food pantry. He has $36, and can carry up to 20 pounds of food in his backpack.

horrorfan [7]

Answer:

solutions: (2, 10), (4, 5)
non-solutions: all other points

Step-by-step explanation:

It can be useful to graph the inequalities related to Tyler's limits of money and weight.

1x +3y ≤ 36 . . . . . . the limit on the cost of the items Tyler can afford

1x +1.5y ≤ 20 . . . . . the limit on the weight of the items Tyler can carry

Then plotting the given points shows that only (2, 10) and (4, 5) are in the doubly-shaded area that is the solution space. The other points are not a solution.

6 0

3 years ago