Answer: 60.1K
Explanation:
Initial volume of gas V1 = 423.3mL
Initial temperature T1 = 49.2°C
Convert temperature in Celsius to Kelvin
( 49.2°C + 273 = 322.2K)
Final temperature T2 = ?
Final volume V2 = 79mL
According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.
Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2
423.3mL/322.2 = 79mL/T2
To get the value of T2, cross multiply
423.3mL x T2 = 322.2K x 79mL
423.3mL x T2 = 25453.8
T2 = (25453.8/423.3mL)
T2 = 60.1K
Thus, the new temperature of the gas is 60.1K
Cao + H2O ---->Ca(OH)2
Calculate the number of each reactant and the moles of the product
that is
moles = mass/molar mass
The moles of CaO= 56.08g/ 56.08g/mol(molar mass of Cao)= 1mole
the moles of water= 36.04 g/18 g/mol= 2.002moles
The moles of Ca (OH)2=74.10g/74.093g/mol= 1mole
The mass of differences of reactant and product can be therefore
explained as
1 mole of Cao reacted completely with 1 mole H2O to produce 1 mole of Ca(OH)2. The mass of water was in excess while that of CaO was limited
Use Boyle's Law of Pressure: P1 x V1 = P2 x V2. Givens: P1=0.9 atm V1= 4 P2= 0.9 atm Find: V2 Equation: 0.9 atm x 4 x 4 L = 0.20 atm x V2Solve: 36 atmL= 0.20 atm x V2 18 : = V2 Short answer: The new volume is 104 ml.
Answer:
Accuracy is the closeness to the specific target and precision is the closeness of the measurements to each other.
Answer:
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