Hi there!
We can use the work-energy theorem to solve.
Recall that:
The initial kinetic energy is 0 J because the crate begins from rest, so we can plug in the given values for mass and final velocity:
Now, we can define work:
Now, plug in the values:
Solve for theta:
Equations of motion (EoM) use EoM <span>v2=u2+2ax</span> to establish velocities at positions shown in blue in drawing from EoM v=u+at for final 1 second of flight time, we can say v=u+g(1) <span><span>2gH−−−−√</span>=<span><span>2g1625H</span>−−−−−−√</span>+g</span><span> then, solve for H [in terms of g]
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Answer:
it goes up until we help it to but the moment we stop support it gets affected by gravity and goes back
Explanation:
Question:
The options are
a. Technician A only
b. Technician B only
c. Both A and B
d. Neither A nor B
Answer:
The correct option is
d. Neither A nor B
Explanation:
Here, we note that to locate the receiver/driers we look at the high-pressure side of refrigerant system normally around the tubes in between the expansion valve outlet and the condenser outlet and connected to the condenser.
While the accumulator can be found, attached to the evaporator outlet within the low pressure side of the refrigerant system.
Therefore, neither Technician A nor B is correct.
