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ziro4ka [17]
4 years ago
8

How does hitting a ball with a tennis racquet involve action and reaction forces?

Physics
1 answer:
iragen [17]4 years ago
5 0

Answer:

In a tennis match, the racket exerts the action force on the ball and, as the ball hits it, it exerts an equal and opposite reaction force on the racket. The rocket launches because it pushes on the gas coming out the back end for the action force, while the gas pushes the rocket upward with a reaction force.

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A charge of 240C flows through a wire in 3 minutes. Find the electric current flowing through it.
o-na [289]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Use this equation:

Q = IT

Rearrange for I

I = Q/T

Substitute in the values:

I = 240/3

I = 80

The electric current is 80 amps.

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

7 0
3 years ago
Read 2 more answers
It is desired to create a particle of mass 7920 MeV/c^2 in a head-on collision between a proton and an antiproton (each having a
Olegator [25]

Answer:

v=0.9714c

Explanation:

The kinetic energy possessed by  particles will be  

K.E=\frac{1}{2}Mc^2

where,

M is the mass of the particle (7920938.3 MeV/c²)

c is the speed of the light

Also,

energy of the proton particle = \frac{m_pc^2}{\sqrt{1-\frac{v^2}{c^2}}}

where,

v is the velocity

m_p is the mass of the proton (938.3 MeV/c²)

since the energy is equal

thus,

\frac{m_pc^2}{\sqrt{1-\frac{v^2}{c^2}}}=\frac{1}{2}Mc^2

or

1-\frac{v^2}{c^2}=[\frac{2m_p}{M}]^2

substituting the values in the above equation, we get

1-\frac{v^2}{c^2}=[\frac{2\times 938.3 }{7920}]^2

or

v=0.9714c

Hence,<u> the speed necessary for the specified condition to occur is </u><u>0.9714 times the speed of the light</u>

5 0
3 years ago
A satellite with a mass of 120 kg fires its rocket thrusters, which give an impulse of 7440 kg-m/s. What was the total change in
Marat540 [252]

From the calculation and the momentum of the body, the velocity is 62 m/s

<h3>What is momentum?</h3>

The term momentum refers to the product of mass and velocity. Now recall that the rate of change of momentum is equal to the impressed force.

Hence;

7440 kg-m/s = 120 kg * v

v= 7440 kg-m/s/120 kg

v =  62 m/s

Learn more about momentum:brainly.com/question/24030570

#SPJ1

3 0
2 years ago
Write the first equation of motion. Under what condition(s) is this equation valid?​
Zepler [3.9K]

Explanation:

The first equation of motion in kinematics is given by :

v=u+at .....(1)

u is initial speed

a is acceleration

v is final speed

t is time

Equation (1) is valid when the object is moving with constant acceleration. This equation gives relation between velocity and time.

3 0
3 years ago
If you precisely measure the position of a particle, you
pochemuha
<h2>Answer: destroy all information about its speed or momentum</h2>

The Heisenberg uncertainty principle postulates that the fact that <u>each particle has a wave associated with it</u>, imposes restrictions on the ability to determine its <u>position</u> and <u>speed</u> at the same time.  

In other words:  

<h2>It is impossible to measure <u>simultaneously </u>(according to quantum physics), and with absolute precision, the value of the position and the momentum (linear momentum) of a particle.  </h2>

So, the greater certainty is seeked in determining the position of a particle, the less is known its linear momentum and, therefore, its mass and velocity.  

It should be noted that this uncertainty does not derive from the measurement instruments, but from the measurement itself. Because, even with the most precise devices, the uncertainty in the measurement continues to exist.  

Thus, in general, the greater the precision in the measurement of one of these magnitudes, the greater the uncertainty in the measure of the other complementary variable.  

3 0
3 years ago
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