Answer:
Explanation:
Follow the schematic in which point A is the warehouse and point D is the destination.
Now we observe the triangle constructed :
here:
&
As we know that displacement is the shortest distance between two points.
<u>Using Pythagoras theorem:</u>
Answer:
Object should be placed at a distance, u = 7.8 cm
Given:
focal length of convex lens, F = 16.5 cm
magnification, m = 1.90
Solution:
Magnification of lens, m = -
where
u = object distance
v = image distance
Now,
1.90 =
v = - 1.90u
To calculate the object distance, u by lens maker formula given by:
u = 7.8 cm
Object should be placed at a distance of 7.8 cm on the axis of the lens to get virtual and enlarged image.
Answer:
a) Q1=Q2=480μC V1=240V V2=60V
b) Q1=96μC Q2=384μC V1=V2=48V
c) Q1=Q2=0C V1=V2=0V
Explanation:
Let C1 = 2μC and C2=8μC
For part (a) of this problem, we know that charge in a series circuit, is the same in C1 and C2. Having this in mind, we can calculate equivalent capacitance first:
For part (b), the capacitors are in parallel now. In this condition, the voltage is the same for both capacitors:
So,
Total charge is the same calculated for part (a), so:
Solving for Q2:
Q2 = 384μC Q1 = 96μC.
Therefore:
V1=V2=48V
For part (c), both capacitors would discharge, since their total voltage of 300V would by applied to a wire (R=0Ω). There would flow a huge amount of current for a short period of time, and capacitors would be completely discharged. Q1=Q2=0C V1=V2=0V
Answer:
The speed of the spacecraft should be 719.35m/s
Explanation:
if the spacecraft is orbiting the planet with a circular orbit, the gravitational force must act as a centripetal force. This means:
In this case, the pluto's mass M is 1.3099·10^22 kg. The radius of the planet R is 1188.3Km and G is the gravitational constant. Therefore: