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gayaneshka [121]
3 years ago
8

How do I find the inverse of this problem?

Mathematics
1 answer:
IgorLugansk [536]3 years ago
8 0

Answer:

g=n . n=g

Step-by-step explanation:  g - 1 / n - 2 7

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Sam buys 3 different types of fruit in 3/4 pounds basket. Maria has 1 1/4 pound fruit. How many pounds of fruit do they have alt
uysha [10]

Answer: 2 pounds

Step-by-step explanation: hope this helps:)

5 0
3 years ago
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I don't get how to do #10 someone help plez
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3 0
3 years ago
Find the area of a triangle with a =33, b =51, and c =42.
PolarNik [594]

Answer:

d. 690.1 units²

Step-by-step explanation:

1. You can use the Heron's formula to calculate the area of the triangle, which is:

K=\sqrt{s(s-a)(s-b)(s-c)}

Where:

s=\frac{a+b+c}{2}

2. Calculate s:

s=\frac{33+51+42}{2}\\s=63

3. Substitute values into the formula shown above and calculate the area, as following:

K=\sqrt{63(63-33)(63-51)(63-42)}\\K=690.1units^{2}

4. Therefore, the area is 690.1 units².

4 0
3 years ago
If the area of triangle ABC= 25 square feet, then the area of the rectangle ABCD is:
UkoKoshka [18]
A rectangle has 2 triangle
∴ 25 feet² × 2 = 50 feet²
5 0
4 years ago
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Two groups of students were asked how many hours they spent reading each day. The table below shows the numbers for each group:
marta [7]

Solution:

Data represented as number of hours spent in studying by Group A Students:

 1,2,1,1,3,3,2,2,3

Arranging it in ascending order: 1,1,1 ,2, 2, 2, 3, 3, 3,

As number of terms is odd, The median will be middle value of observation.Which is 2.

The Data arranged in ascending order are , (1,1,1,2),2(2,3,3,3).

Median of (1,1,1,2) = Q_{1}=1

Median of (2,3,3,3)=Q_{3}=3

D_{1}=Interquartile Range =Q_{3}-Q_{1}=3-1=2

For Data Set 2,

The Data for group B students are:  3   2 3 2 2 2 1 1 2

Arranging in ascending order: 1,1,2,2,2,2,2,3,3

total number of observation = 9

Median = 2

Arranging the data as : (1,1,2,2) 2,(2,2,3,3)

Median of (1,1,2,2)= Number of observation is 4 which is even , so Median=Q_{1} =  \frac{1+2}{2}=\frac{3}{2}

Median of (2,2,3,3)=Q_{3}= \frac{3+2}{2}=\frac{5}{2}

S=Interquartile Range = Q_{3}-Q_{1}=\frac{5}{2}-\frac{3}{2}=1

D_{1}= S + 1

Interquartile range for Group A Students =Interquartile range for Group B students + 1

Option (D) The interquartile range for Group A employees is 1 more than the interquartile range for Group B students is true.

8 0
3 years ago
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