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taurus [48]
3 years ago
15

Pls check for me !! thank you.​

Chemistry
1 answer:
Olin [163]3 years ago
4 0

Answer:

52 mL of H₂O.

Explanation:

The balanced equation for the reaction is given below:

2H₂ + O₂ —> 2H₂O

From the balanced equation above,

2 mL of H₂ reacted with 1 mL of O₂ to produce 2 mL of H₂O.

Finally, we shall determine the volume of H₂O that will be produced by the reaction of 52 mL of H₂ at the same temperature and pressure.

This can be obtained as follow:

From the balanced equation above,

2 mL of H₂ reacted to produce 2 mL of H₂O.

Therefore, 52 mL of H₂ will also react to produce 52 mL of H₂O.

Thus, 52 mL of H₂O were obtained from the reaction.

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Both have the same balance on a weight with. 2 dimensional figures on the area formula

Explanation:

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2 years ago
A 50 L cylinder is filled with argon gas to a pressure of 10130.0 kPa at 300°C. How many moles of argon gas does the cylinder co
KengaRu [80]
In this problem, we need to use the ideal gas law. The following is the formula used in ideal gas law: PV = nRT, where n refers to the moles and R is the gas constant.

Given 
P = 10130.0 kPa 
V = 50 L
T = 300 degree celcius + 273.15 = 573.15 K
R = 8.314 L. kPa/K.mol

Solution
To get the moles which represent the "n" in the formula, we need to rearrange the equation.

PV = nRT                      PV
----    ------    --->    n = --------
 RT     RT                       RT

          10130.0 kPa  x 50 L
n= ---------------------------------------------
       8.314 L. kPa/K.mol  x 573.15 K
             506,500 
  =  ----------------------------
         4,765.17  mol K

=106.29 mol Ar

So the moles of argon gas is 106.29 moles 
8 0
3 years ago
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What is "X" in the following reaction?
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Fynjy0 [20]

Answer:

Reagent A: PBr₃

Reagent B: Mg in Et₂O.

Explanation:

Hello,

In this case, your facing a problem in which a carboxylic acid is produced starting by an alcohol. More specifically, cyclopentanol must react with phosphorous tribromide in order to yield bromocyclopentane which is more likely to produce a carboxylic acid, therefore, reagent A is PBr₃.

On the other hand, by means of the production of the specified product, bromocyclopentane must react with carbon dioxide and magnesium in diethyl ether in acidic media to promote the production of the cyclopentanoic acid via the grignard reaction (substitution of the bromine by the carboxyle group), therefore, reagent B is Mg in Et₂O.

Best regards.

8 0
3 years ago
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