Question

Solve A and B using energy considerations.

Answer 1

 Use the kinematic equation vf^2 = vi^2 + 2ad where; 
vf = ? 
vi = 0 m/s 
a = 9.8 m/s^2 
d1 = 10 m 
d2 = 25 m 

final velocity at the ground (d1): vf = sqrt(2)(9.8)(10) = 14 m/s 
final velocity to the bottom of the cliff (d2): vf = sqrt(2)(9.8)(25) = 22.14 m/s