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ad-work [718]
2 years ago
6

2. If a football field is 100.0 yards long and 52.7 yards wide, how long is it in inches?

Chemistry
2 answers:
AURORKA [14]2 years ago
7 0

100 yards = 300 feet = <u>3,600 inches LONG.</u> (Does not include the touchdown zone)

52.7 yards = 158.1 feet = <u>1,897.2 inches WIDE.</u>

If you're looking for AREA in inches, then it's <u>6,829,920 SQUARE inches.</u>

<u></u>

kogti [31]2 years ago
6 0
100 yards is 3,600 inches
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Calculate the empirical formula for a compound containing 67.6% Hg 10.8% S 21.6% O
pashok25 [27]

Answer:

HgSO₄

Explanation:

% => g => moles => ratio => reduce => empirical ratio

%Hg = 67.6% => 67.6g/201g/mol = 0.34mol

%S    = 10.8% => 10.8g/32g/mol = 0.34mol

%O   = 21.6% => 21.6g/16g/mol = 1.35mol

Hg:S:O => 0.34:0.34:1.35

Reduce to whole number ratio by dividing by the smaller mole value...

Hg:S:O => 0.34/.34:0.34/.34:1.35/.34 => Empirical Ratio = 1:1:4

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3 years ago
How can grocery carts with different masses have the same acceleration?
Nezavi [6.7K]

Answer:

Yes

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2 years ago
Solve fasttt<br><br> C7H17+O2=CO2+H2O<br><br> Balancing Equations
sertanlavr [38]

Answer:

The answer to your question is

                                        4C₇H₁₇  + 45 O₂    ⇒   28 CO₂   +  34H₂O  

Explanation:

Write the equation

                                        C₇H₁₇  +    O₂    ⇒    CO₂   +    H₂O  

Process

1.- Check if the equation is balanced

                                 Reactants            Element              Products

                                        7                          C                           1

                                       17                          H                          2

                                        2                          O                          3

As the number of reactants and products is different, we conclude that the reaction is unbalanced.

2.- Write a coefficient "7" to CO₂   and a coefficient of 17/2 to H₂O

                                      C₇H₁₇  +    O₂    ⇒   7CO₂   +  \frac{17}{2}H₂O  

                                 Reactants            Element              Products

                                        7                          C                           7

                                       17                          H                          17

                                        2                          O                          51/2

3.- Write a coefficient of 45/2 to the O₂, and multiply all the equation by 2.

                         4C₇H₁₇  + 45 O₂    ⇒   28 CO₂   +  34H₂O  

                  Reactants            Element              Products

                        28                          C                        28

                        68                          H                        68

                        90                          O                        90

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