Answer:
ASA and AAS
Step-by-step explanation:
We do not know if these are right triangles; therefore we cannot use HL to prove congruence.
We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.
We are given that EF is parallel to HJ. This makes EJ a transversal. This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent. We also know that ∠EGF and ∠HGJ are vertical angles and are congruent. This gives us two angles and a non-included side, which is the AAS congruence theorem.
Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent. Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.
She worked for five hours on Saturday.
Step by step: 3 hours × $6.50= $19.50
then take the amount of money she made in total and subtract what she made on Friday to find how much she made on Saturday
$52 - $19.50= $32.50
Now take how much she made on Saturday and divide that by $6.50 to find how many hours she worked on Saturday
$32.50 ÷ $6.50= 5 hours
Answer:
The 3rd one, The 1st one and The last one.
Step-by-step explanation:
If there are no options to choose from I’d say 25 but if there are options please post them
Answer:
(8√2) / 15
Step-by-step explanation:
A curve bounded by the y-axis is represented by in terms of dy;
When the curve crosses the y-axis, x will be 0. In this case x is the function of t, so we have to solve for x(t) = 0;
0 = t^2 + 2t --- (1)
Solution(s) => t = 0, t = 2
dy = (1/2 * 1/√t)dt --- (2)
Our solutions (0, 2) are our limits. The area of the curve is in the form 
, so now let's introduce the limits of integration, x(t) and dy/dt. Remember, dy/dt = (1/2 * 1/√t) (second equation). 1/2 * 1/√t can be rewritten as 1/2 * t^(-1/2)....
![A\:=\:\int _2^0\:\left(t^2-2t\right)\left(\frac{1}{2}t^{-\frac{1}{2}}\right)dt\\\\= \int _2^0\:\left(\frac{1}{2}t^{\frac{3}{2}}-t^{\frac{1}{2}}\right)dt\\\\= \left[\frac{t^{\frac{5}{2}}}{5}-\frac{2t^{\frac{3}{2}}}{3}\right]_2^0\\\\= 0\:-\:\left(\frac{4\sqrt{2}}{5}-\frac{4\sqrt{2}}{3}\right)\\\\= \frac{8\sqrt{2}}{15}](https://tex.z-dn.net/?f=A%5C%3A%3D%5C%3A%5Cint%20_2%5E0%5C%3A%5Cleft%28t%5E2-2t%5Cright%29%5Cleft%28%5Cfrac%7B1%7D%7B2%7Dt%5E%7B-%5Cfrac%7B1%7D%7B2%7D%7D%5Cright%29dt%5C%5C%5C%5C%3D%20%5Cint%20_2%5E0%5C%3A%5Cleft%28%5Cfrac%7B1%7D%7B2%7Dt%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D-t%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5Cright%29dt%5C%5C%5C%5C%3D%20%5Cleft%5B%5Cfrac%7Bt%5E%7B%5Cfrac%7B5%7D%7B2%7D%7D%7D%7B5%7D-%5Cfrac%7B2t%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%7D%7B3%7D%5Cright%5D_2%5E0%5C%5C%5C%5C%3D%200%5C%3A-%5C%3A%5Cleft%28%5Cfrac%7B4%5Csqrt%7B2%7D%7D%7B5%7D-%5Cfrac%7B4%5Csqrt%7B2%7D%7D%7B3%7D%5Cright%29%5C%5C%5C%5C%3D%20%5Cfrac%7B8%5Csqrt%7B2%7D%7D%7B15%7D)
Your solution is 8√2 / 15
