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3 years ago

How many moles of Mg are consumed when 0.34 moles oxygen gas completely reacts?

Chemistry

1 answer:

Sveta_85 [38]3 years ago

4 0

Answer:

0.34 moles of oxygen consumed 0.68 moles of magnesium

Explanation:

Given data:

Moles of magnesium = ?

Moles of oxygen = 0.34 mol

Chemical equation:

2Mg + O₂ → 2MgO

Now we will compare the moles of oxygen and magnesium:

O₂ : Mg

1 : 2

0.34 : 2×0.34 = 0.68 mol

Thus 0.34 moles of oxygen consumed 0.68 moles of magnesium.

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$\Delta G^0 _{rxn} = 207.6\ kJ/mol$

The equilibrium constant determined from the partial pressure denoted as $K_p$ can be expressed as :

$K_p = \dfrac{(22.20)^2}{(22.20)^2 \times (22.20)}$

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$\Delta G = \Delta G^0 _{rxn} + RT \ lnK$

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R = gas constant = 8.314 × 10⁻³ kJ

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$\Delta G =207.6 + 2.4788191 \times \ ln(0.045)$

$\Delta G =207.6+ (-7.687048037)$

$\Delta G =$ 199.912952 kJ

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