Answer:
The element iodine forms an anion with the charge -1. The symbol for this ion is I⁻¹, and the name is iodide. The number of electrons in this ion is 7.
Explanation:
Hello,
In this case, we have to consider iodine has the capacity to accept the electrons lost by other elements such as metals or hydrogen by becoming negatively charged. Such phenomena makes iodine to form an anion (negatively charged) with the charge -1, since it only needs one electron to attain the octet. Moreover, the symbol of such ion is I⁻¹ and its name is iodide. By cause of the aforementioned, the number of electrons it has is 7 since at its outer shell seven electrons are found (see electron configuration Kr,5s²,5p⁵).
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<u>We are given:</u>
Mass of NaCl in the given solution = 22.3 grams
Volume of the given solution = 2 L
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<u>Number of Moles of NaCl:</u>
We know that the number of moles = Given mass / Molar mass
Number of moles = 22.3 / 58.44 = 0.382 moles
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<u>Molarity of NaCl in the Given solution:</u>
We know that Molarity of a solution = Moles of Solute / Volume of Solution(in L)
Molarity = 0.382 / 2
Molarity = 0.191 M
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Answer:
e, arrow b
Explanation:
what kind of monster made that answer selection...?!
so the second to last one in the answer section.
Answer:
H-F> H-O> O-F
while H-H is nonpolar.
Explanation:
The bond is polar when electronegativity difference of both bonded atom is greater than 0.4.
Electronegativity values of O. F and H are
O = 3.4
H = 2.2
F = 3.98
For O-F
3.98 - 3.4 = 0.58
For H-F
3.98 - 2.2 = 1.78
For H-O
3.4 - 2.2 = 1.2
For H-H
2.2 -2.2 = 0
So H-H is nonpolar.
Attached is the balanced chemical equation xx
