This is false. Current is the speed of the charge, 1 amp of current is 1 coulomb per second. So you can imagine the current of a circuit as the current of a river. In a parallel circuit, the river breaks into two separate streams. Some of the water goes down one river, some goes down the other. However, the total amount of water/coulombs never changes. This means that some of the total current will go down one river, and one the other. However, with less coulombs now the current will decrease.
Long story short, since there are two paths, the charge will split and depending on the resistance of each parallel stream a different amount of charge will go down each branch.
<u>Order sequence of steps that are involved in the production of work by a four-stroke heat engine as follows:
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- Piston moves down, allowing fuel-air mixture to enter intake valve
- Piston moves up, compressing gas and causing gas to increase its temperature
- Combustion as gas is still compressed; increase in energy from combustion pushes piston down
- Piston moves up, pushing burned gases through exhaust valve: Spark plug fires, causing
Answer: Options D, A, C and B
<u>Explanation:
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There are four basic steps of a four stroke engine- Intake, Combustion, Power and Exhaust. The first step is the intake of air plus fuel mixture in the combustion chamber. At this time, the piston moves down. Now when the chamber is closed, the spark plug ignites fire which expands the fuel gases.
The gases push down, piston and crankshaft rotates in this way. Once the gases the combustion is done, there is plenty of space in the chamber that makes the piston moves up. In this way a complete cycle is completed and the crankshaft moves. That’s the working of this four stroke engines.
<span>they took advantage of innovations in sailing technolgy that allowed ships such as the caravel to sail against the wind.</span>
you could make a self propelled car all you need is cardboard, wheels, and a balloons or rubber bands
The mass on the left has a downslope weight of
W1 = 3.5kg * 9.8m/s² * sin35º = 19.7 N
The mass on the right has a downslope weight of
W2 = 8kg * 9.8m/s² * sin35º = 45.0 N
The net is 25.3 N pulling downslope to the right.
(a) Therefore we need 25.3 N of friction force.
Ff = 25.3 N = µ(m1 + m2)gcosΘ = µ * 11.5kg * 9.8m/s² * cos35º
25.3N = µ * 92.3 N
µ = 0.274
(b) total mass is 11.5 kg, and the net force is 25.3 N, so
acceleration a = F / m = 25.3N / 11.5kg = 2.2 m/s²
tension T = 8kg * (9.8sin35 - 2.2)m/s² = 27 N
Check: T = 3.5kg * (9.8sin35 + 2.2)m/s² = 27 N √
hope this helps. :)
