what?theres no picture. what does this mean?
Answer:
The magnitude of the average induced emf in the loop is 0.1 volts.
Explanation:
let Ф be the flux in the loop, B be the magnetic field and A be the area of the loop.
the induced emf in the loop is given by:
ε = - dФ/dt
= - d(B×A)/dt
= - A×d(B)/dt
= - π×r^2×d(B)/dt
= - π×(0.40)^2×(0.20 - (-0.30))/(2.5 - 0)
= 0.1 volt
Therefore, the magnitude of the average induced emf in the loop is 0.1 volts.
This question is asking the force on the rope. We can find this by using centripetal acceleration, then multiply by the ice skater's mass.
First we need to find the centripetal acceleration, which is a = v^2/r
We are given v and r, so we solve for a.
a = [(5.14m/s)^2]/(0.525m) = 50.323 m/s^2
Next multiply by the ice skater's mass (because F=ma) which is 44.6 kg
We then get F = (50.323m/s^2)(44.6kg) = 2244.407924N
Divide by 10^3 to get kN, we get:
2.244kN
Hope this helps!
Answer:Smaller Than the object and right-side up
Explanation:
