Sketch a reaction progress curve for a reaction that has an activation energy of 22 kj and the total energy change is -103kj.

Physics

1 answer:

crimeas [40]4 years ago

8 0

Answer:

Do find the answer in the attachment herein.

Explanation:

From the attached diagram:

I. Activation energy = Activated complex - ∆H(reactants)

Activation energy = 162-140 = 22Kj.

II. ∆H(reaction) = ∆H(products) - ∆H(reactants)

∆H(reaction) = 37 - 140 = -103Kj.

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