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madreJ [45]
3 years ago
11

The chemical reaction shown above takes place in a closed system. What is true about the system while the reaction occurs? A. Th

e total number of particles in the system decreases. B. The total mass of the particles in the system stays the same. C. The total mass of the particles in the system increases. D. The total number of particles in the system increases.
Chemistry
1 answer:
Ede4ka [16]3 years ago
5 0

<u>Answer:</u> In a chemical reaction, the total mass of the particles in the system stays the same

<u>Explanation:</u>

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.  

This also means that total mass on the reactant side must be equal to the total mass on the product side in a chemical reaction.

Every balanced chemical reaction follows law of conservation of mass.

<u>For Example:</u> Formation of water molecule

2H_2+O_2\rightarrow 2H_2O

Total mass on reactant side = [2(2\times 1)+(2\times 16)]=36g/mol

Total mass on product side = [2((2\times 1)+16)]=36g/mol

Hence, in a chemical reaction, the total mass of the particles in the system stays the same

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A slurry of flakes soybeans weighing a total of 100 kg contains 75 kg of inert solids and 25 kg of solution with 10 wt% oil and
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Answer:

the amounts and compositions of the overflow V1 and underflow L1 leaving the stage are 75kg and 125kg respectively.

Explanation:

Let state the given parameters;

Let A= solvent (hexane)

B= solid(inert soiid)

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F_{solution} = mass of solvent + mass of oil (i.e A+C)

<u>Feed Phase:</u>

Total feed (i.e slurry of flakes soybeans)= 100kg

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F= mass of solvent + mass of oil (i.e A+C)

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C= Mass of oil= 0(kg)

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mass of solutions = A+C = 0+100kg

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<u>Underflow:</u>

underflow = L₁ = (unknown) ???

L₁ = E₁ + B

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i.e N₁ = \frac{mass B}{mass(A+C)}

solution in underflow E₁ = Mass (A+C)

<u>Overflow:</u>

Overflow = V₁ = (unknown) ???

solution in overflow V₁ = Mass (A+C)

This is because, B = 0 in overflow

Solid Balance: (since the solid is inert, then is said to be same in feed & underflow).

solid in feed = solid in underflow = 75

75=  E₁ × N₁

75 =  E₁ × 1.5

E₁ = 50kg

Underflow L₁ = E₁ × B

= 50 + 75

=125kg

The Overall Balance: Feed + Solvent = underflow + overflow

100 + 100 = 125 + V₁

V₁ = 75kg

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