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Marat540 [252]
3 years ago
10

How should a stopper be handled after is has been removed from a reagent bottle?

Chemistry
1 answer:
anzhelika [568]3 years ago
6 0
<span>The stopper should be held until it can be safely re-inserted. Placing it on any other type of surface or table could run the risk of cross-contamination. This could cause issues with the reagent when the stopper is replaced.</span>
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Ca(OH)2(aq)+HNO3(aq)→H2O(l)+Ca(NO3)2(aq)
shtirl [24]

what are we doing in that question

Explanation:

I dunno know

6 0
3 years ago
A Series of choices between two characteristics that is used to identify an organism is called a
Zielflug [23.3K]

Answer: Dichotomous

Using a Dichotomous Key to Identify Organisms

A dichotomous key is a tool used by biologists to identify organisms in a group through a process of answering yes or no questions about the organism. Dichotomous means 'divided into two parts', as each question about an organism has two choices.

8 0
4 years ago
What branch of chemistry studies the flow of electrons?
grin007 [14]

Answer:

Your answer is B, Electrochemistry!

Explanation:

This is the part of chemistry that studies the chemical process in which electrons flow. This flow is called electricity. Electricity is generated by the flow of electrons, from one element to another element. This reaction is called oxidation reduction.

6 0
2 years ago
The specific heat of liquid bromine is 0.226 J/g-K. How much heat (J) is required to raise the temperature of 10.0 mL of bromine
Viefleur [7K]

Answer:

16.2 J

Explanation:

Step 1: Given data

  • Specific heat of liquid bromine (c): 0.226 J/g.K
  • Volume of bromine (V): 10.0 mL
  • Initial temperature: 25.00 °C
  • Final temperature: 27.30 °C
  • Density of bromine (ρ): 3.12 g/mL

Step 2: Calculate the mass of bromine

The density is equal to the mass divided by the volume.

ρ = m/V

m = ρ × V

m = 3.12 g/mL × 10.0 mL

m = 31.2 g

Step 3: Calculate the change in the temperature (ΔT)

ΔT = 27.30 °C - 25.00 °C = 2.30 °C

The change in the temperature on the Celsius scale is equal to the change in the temperature on the Kelvin scale. Then, 2.30 °C = 2.30 K.

Step 4: Calculate the heat required (Q) to raise the temperature of the liquid bromine

We will use the following expression.

Q = c × m × ΔT

Q = 0.226 J/g.K × 31.2 g × 2.30 K

Q = 16.2 J

7 0
3 years ago
Assume that 25 ml of 0.440M NaCl are added to 25 ml of 0.320M AgNO3.
Genrish500 [490]
The balanced chemical equation would be as follows:

<span>NaCl + AgNO3 -> NaNO3 + AgCl

We are given the amounts of the reactants. We need to determine first which one is the limiting reactant. We do as follows:

0.0440 mol/L NaCl (.025 L) = 0.0011 mol NaCl -----> consumed completely and therefore the limiting reactant
0.320 mol/L AgNO3 (0.025 L) = 0.008 mol AgNO3

0.0011 mol NaCl ( 1 mol AgCl / 1 mol NaCl) = 0.0011 AgCl precipitate produced


</span>
8 0
3 years ago
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