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nignag [31]
11 months ago
12

Calculate the entropy change for the reaction: Fe2O3(s) +3C(s) -> 2Fe(s) + 3CO(g)Entropy data:Fe2O3(s): 90 J/K molC(s): 5.7 J

/K molFe(s): 27.2 J/K molCO(g): 198 J/K molA. +129.5 J/K molB. -129.5 J/K molC. +541.3 J/K molD. +320.9 J/K mol
Chemistry
1 answer:
Annette [7]11 months ago
5 0

Explanation:

We are given: entropy of Fe2O3 = 90J/K.mol

: entropy of C = 5.7J/K.mol

: entropy of Fe = 27.2J/K.mol

: entropy of CO = 198J/K.mol

\begin{gathered} \Delta S\text{ = S}_{products}-S_{reactants} \\  \\ \text{       = \lparen3}\times198+2\times27.2)-(3\times5.7+90) \\  \\ \text{       = 541.3J/K.mol} \end{gathered}

Answer:

The correct answer is C.

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