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nignag [31]
1 year ago
12

Calculate the entropy change for the reaction: Fe2O3(s) +3C(s) -> 2Fe(s) + 3CO(g)Entropy data:Fe2O3(s): 90 J/K molC(s): 5.7 J

/K molFe(s): 27.2 J/K molCO(g): 198 J/K molA. +129.5 J/K molB. -129.5 J/K molC. +541.3 J/K molD. +320.9 J/K mol
Chemistry
1 answer:
Annette [7]1 year ago
5 0

Explanation:

We are given: entropy of Fe2O3 = 90J/K.mol

: entropy of C = 5.7J/K.mol

: entropy of Fe = 27.2J/K.mol

: entropy of CO = 198J/K.mol

\begin{gathered} \Delta S\text{ = S}_{products}-S_{reactants} \\  \\ \text{       = \lparen3}\times198+2\times27.2)-(3\times5.7+90) \\  \\ \text{       = 541.3J/K.mol} \end{gathered}

Answer:

The correct answer is C.

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2. Which of the following is a mixture?
Ganezh [65]

Hey there!

Your answer is D. salt water  

A mixture has more than one substance.

Salt water is made up of multiple different substances, salt (NaCl) and water (H₂O).

Carbon dioxide (CO₂), water vapor (H₂O), and oxygen gas (O₂) are each just one substance.

Hope this helps!

7 0
3 years ago
How does the concentration of a gas in solution change when the partial pressure of the gas above the solution increases?
irakobra [83]
Because the concentration of molecules in the gas phase increases with increasing pressure, the concentration of dissolved gas molecules in the solution at equilibrium is also higher at higher pressures
5 0
3 years ago
A steel tank contains carbon dioxide at a pressure of 13.0 atm when the temperature is 34oC. What will be the internal gas press
morpeh [17]

Answer:

D. 15.8atm

Explanation:

Given parameters:

Initial pressure = 13atm

Initial temperature  = 34°C = 34 + 273  = 307K

Final temperature  = 100°C = 100 + 273  = 373K

Unknown:

Final pressure  = ?

Solution:

To solve this problem, we apply a derivation of the combined gas law taking the volume as a constant.

The expression is shown mathematically below;

        \frac{P_{1} }{T_{1} }   = \frac{P_{2} }{T_{2} }

P and T pressure and temperature values

1 and 2 are initial and final states

 Insert the parameters and solve for T₂;

    \frac{13}{307}   = \frac{P_{2} }{373}  

        P₂  = 15.8atm

4 0
3 years ago
An ore is to be analyzed for its iron content by an oxidation-reduction titration with permanganate ion. A 4.230 g sample of the
Leya [2.2K]

Answer:

See explanation

Explanation:

The balanced redox reaction equation is;

8H+ + MnO4^- + 5Fe2+ ---------> Mn2+ + 5Fe3+ + 4H2O

Amount of KMnO4 reacted = 31.60/1000 * 0.05120 = 1.62 * 10^-3 moles

From the reaction equation;

1 mole of MnO4^- reacted with 5 moles of Fe2+

1.62 * 10^-3 moles will react with 1.62 * 10^-3 moles * 5/1 = 8.1 * 10^-3 moles

Mass of Fe2+ reacted = 8.1 * 10^-3 moles  *  56 g/mol

Mass of Fe2+ reacted = 0.45 g

Amount of iron in the sample =  0.45 g

Percentage of iron in the sample;

0.45 g/4.230 g  * 100 = 10.6 %

8 0
3 years ago
Balance the following equations:
lesya [120]
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2>

(I) N_{2} + 3H_{2} --> 2NH_{3}

(II) P_{4}  + 5O_{2}  --> 2P_{2} O_{5}

(III) 2NaF + Br_{2}  -->2NaBr + F_{2}

(IV) 2ZnS + 3O_{2} --> 2ZnO + 2SO_2

(V) Pb(NO_3)_2 + 2NaCl --> 2NaNO_3 + PbCl_2

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>

7 0
3 years ago
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