Question

5.1169 mol of Ne is held at 0.9148 atm and 911 K. What is the volume of its container in liters?

Answer 1

By applying the Boyle's equation and substituting our given data the volume of the container was found to be 418.14 Litres

Boyle's  Law

Given Data

• number of moles of Ne = 5.1169 mol

• Pressure = 0.9148 atm

• Temperature = 911 K

We know that the relationship between pressure and temperature is given as

PV = nRT

R = 0.08206

Making the volume subject of formula we have

V= nRT/P

Substituting our given data to find the volume we have

V = 5.1169*0.08206*911/0.9148

V = 382.522353554/0.9148

V = 418.14 L

Learn more about Boyle's law here:

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