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Oxana [17]
2 years ago
5

5.1169 mol of Ne is held at 0.9148 atm and 911 K. What is the volume of its container in liters?

Chemistry
1 answer:
sveticcg [70]2 years ago
5 0

By applying the Boyle's equation and substituting our given data the volume of the container was found to be 418.14 Litres

<h3>Boyle's  Law</h3>

Given Data

  • number of moles of Ne = 5.1169 mol
  • Pressure = 0.9148 atm
  • Temperature = 911 K

We know that the relationship between pressure and temperature is given as

PV = nRT

R = 0.08206

Making the volume subject of formula we have

V= nRT/P

Substituting our given data to find the volume we have

V = 5.1169*0.08206*911/0.9148

V = 382.522353554/0.9148

V = 418.14 L

Learn more about Boyle's law here:

brainly.com/question/469270

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2 years ago
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Option B is correct = 1,3

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Balanced chemical equation:

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Step 1:

Left side                      Right side

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Step 2:

C₂H₄ + O₂     →    2CO₂ + H₂O

Left side                      Right side

C = 2                           C = 2

H = 4                           O = 5

O = 2                           H = 2

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C₂H₄ + O₂     →    2CO₂ + 2H₂O

Left side                      Right side

C = 2                           C = 2

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Step 4:

C₂H₄ + 3O₂     →    2CO₂ + 2H₂O

Left side                      Right side

C = 2                           C = 2

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