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Oxana [17]
2 years ago
5

5.1169 mol of Ne is held at 0.9148 atm and 911 K. What is the volume of its container in liters?

Chemistry
1 answer:
sveticcg [70]2 years ago
5 0

By applying the Boyle's equation and substituting our given data the volume of the container was found to be 418.14 Litres

<h3>Boyle's  Law</h3>

Given Data

  • number of moles of Ne = 5.1169 mol
  • Pressure = 0.9148 atm
  • Temperature = 911 K

We know that the relationship between pressure and temperature is given as

PV = nRT

R = 0.08206

Making the volume subject of formula we have

V= nRT/P

Substituting our given data to find the volume we have

V = 5.1169*0.08206*911/0.9148

V = 382.522353554/0.9148

V = 418.14 L

Learn more about Boyle's law here:

brainly.com/question/469270

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The total quantity of heat evolved in converting the steam to ice is determined as  -12,928.68 J.

<h3>Heat evolved in converting the steam to ice</h3>

The total heat evolved is calculated as follows;

Q(tot) = Q1(steam to boiling point) + Q2(boiling point to ice) +Q3(freezing to -42 ⁰C)

where;

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Q = = mcΔθ

where;

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Q(tot) = 2(18)(2.01)(100 - 135) + 2(18)(2.01)(0 - 100) + 2(18)(2.09)(-42 - 0)

Q(tot) = -12,928.68 J

Thus, the total quantity of heat evolved in converting the steam to ice is determined as  -12,928.68 J.

Learn more about heat here: brainly.com/question/13439286

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