Answer:
The percentage yield is 78.2g
Explanation:
Given, mass of propane = 42.8 g , sufficient O2 percent yield = 61.0 % yield.
Reaction - C3H8(g)+5O2(g)------> 3CO2(g)+4H2O(g)
First we need to calculate the moles of propane
Moles of propane =
g.mol-1
= 0.971 moles
So, moles of CO2 from the moles of propane
1 mole of C3H8(g) = 3 moles of CO2(g)
So, 0.971 moles of C3H8(g) = ?
= 2.913 moles of CO2
So theoretical yield = 2.913 moles
44.0 g/mol
= 128.2 g
So, the actual mass of CO2 = percent yield
theoretical yield / 100 %
= 61.0 %
128.2 g / 100 %
= 78.2 g
the mass of CO2 that can be produced if the reaction of 42.8 g of propane and sufficient oxygen has a 61.0 % yield is 78.2 g
The balanced reaction is given as:
<span>2Ca(s)+O2(g)→2CaO(s)
</span>
We are given the amount of oxygen gas to be used for the reaction. This will be the starting point of our calculations.
0.016 mol O2 ( 2 mol CaO / 1 mol O2 ) = 0.032 mol CaO
<span>Therefore, for the reaction, the amount of calcium oxide produced is 0.032 moles.</span>
+3
Hence, the magnetic behaviour of the complex is paramagnetic. The oxidation number of the central metal atom: The oxidation number of the metal iron is +3.
You can eliminate A, C, and D almost instantly if you know that engineers are construction workers. The answer is B.