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jek_recluse [69]
2 years ago
7

If the 50-kg crate starts from rest and achieves a velocity of v = 4 m/s

Physics
1 answer:
Kay [80]2 years ago
6 0

Answer:

P = 227 N

Explanation:

Assuming the crate is on horizontal ground and subject to a horizontal force.

F = ma

P - μmg = ma

P = m(a + μg)

P = m(v²/2s + μg)

P = 50(4²/(2(5))+ 0.3(9.8))

P = 227 N

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Two charges, Q1 and Q2, are separated by 6·cm. The repulsive force between them is 25·N. In each case below, find the force betw
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Answer:

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