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jek_recluse [69]
3 years ago
7

If the 50-kg crate starts from rest and achieves a velocity of v = 4 m/s

Physics
1 answer:
Kay [80]3 years ago
6 0

Answer:

P = 227 N

Explanation:

Assuming the crate is on horizontal ground and subject to a horizontal force.

F = ma

P - μmg = ma

P = m(a + μg)

P = m(v²/2s + μg)

P = 50(4²/(2(5))+ 0.3(9.8))

P = 227 N

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A beam of unpolarized light in air strikes a flat piece of glass at an angle of incidence of 54.2 degrees. If the reflected beam
Stels [109]

Answer:

correct option is B. 1.39

Explanation:

given data

angle of incidence (θ) = 54.2 degrees

to find out

index of refraction of the glass

solution

we know that here reflected beam is completely polarized

so angle of incidence = angle of polarized    ....................1

for reflective index we apply here Brewster law that is

μ = tan(θ)     ...............2

put here θ value we get

μ = tan(54.2)

μ = 1.386

so correct option is B. 1.39

6 0
3 years ago
Read 2 more answers
A crowbar is used as a lever. The effort force of 40 newtons moves 3 meters. The resistance force of 54 newtons moves 2 meters.
Katyanochek1 [597]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below is the solution:

Output work = 108 J. 
<span>Input work = 120 J </span>

<span>Efficiency = 108/120 = 9/10 = 90% </span>

<span>(Energy can be converted to heat in friction at the fulcrum, or useless potential energy distorting the crowbar)</span>

6 0
3 years ago
Read 2 more answers
If you add a battery to a series circuit what will happen to the current in the circuit
Evgen [1.6K]

If there wasn't any battery before, then there was no current
in the circuit before, and there IS one now.  That's just about
the greatest change possible.

If there WAS a battery there before and you added another one
in series with it, then there are a few different possibilities for the
effect on the current in the circuit:

-- If the new battery has the same voltage as the original one,
AND you connect the new one so that they're both in the same
direction, then the current in the circuit will become double the
original current (twice as much as it was before).

-- If the new battery has the same voltage as the original one, AND
you connect the new one so that they're in opposite directions, then
the two batteries cancel each other, the total voltage becomes zero,
and the current in the circuit completely disappears.

-- If the voltage of the two batteries is different AND you connect
the new one so that they're both in the same direction, then the
current in the circuit increases, by a factor of

         (sum of the two battery voltages)
divided by
         (voltage of the original battery alone).

-- If the voltage of the two batteries is different AND you
connect the new one so that they're in opposite directions,
then the current in the circuit decreases, by a factor of

           (difference of the two battery voltages)
divided by
            (voltage of the original battery alone)

and the current flows in the direction of whichever battery has
the greater voltage.  If the new battery has greater voltage than
the original one alone, then the current reverses, and flows in
the opposite direction.

I think that covers all the possibilities.
4 0
3 years ago
A ball with a mass of 2.00 kg is dropped from a height of 10.0 m. 2kg 10 m How long will it take to hit the ground?​
GREYUIT [131]
1.4s.....................
5 0
2 years ago
The sun is 60° above the horizon. Rays from the sun strike the still surface of a pond and cast a shadow of a stick that is stuc
Kipish [7]

Answer:

shadow length 7.67 cm

Explanation:

given data:

refractive index of water is 1.33

by snell's law we have

n_{air} sin30 =n_{water} sin\theta

1*0.5 = 1.33*sin\theta

solving for\theta

sin\theta = \frac{3}{8}

\theta = sin^{-1}\frac{3}{8}

\theta =  22 degree

from shadow- stick traingle

tan(90-\theta) = cot\theta = \frac{h}{s}

s = \frac{h}{cot\theta} = h tan\theta

s = 19tan22 = 7.67 cm

s = shadow length

5 0
3 years ago
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