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2 years ago

If the 50-kg crate starts from rest and achieves a velocity of v = 4 m/s

Physics

1 answer:

Kay [80]2 years ago

6 0

Answer:

P = 227 N

Explanation:

Assuming the crate is on horizontal ground and subject to a horizontal force.

F = ma

P - μmg = ma

P = m(a + μg)

P = m(v²/2s + μg)

P = 50(4²/(2(5))+ 0.3(9.8))

P = 227 N

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What distance will a car traveling at a speed of 15 m/s cover in 300 s?

AnnZ [28]

Distance formula: d = st

d = 15 * 300

d = 4,500m

Best of Luck!

3 0

2 years ago

Explain how the plants of a tropical rain forest contribute to the characteristic hot, humid weather associated with the area. U

Talja [164]

Answer: The atmosphere of trophic rainforest is hot and humid due to high rate of transpiration.

Explanation:

The tropical rainforest is a biome which exhibit rich biodiversity of plants and animals. The average temperatures in this region remain high with warm summer. It remains frost free. The soil is nutrient deficient. Due to hot temperature the rate of transpiration remains high as a result the concentration of the water vapors remain high. This is responsible for increasing the humidity in the atmosphere also this region receives appreciable amount of rainfall annually. The average rainfall range is 200-450 centimeters.

6 0

2 years ago

if the mass is 10 gram and the volume is 7 cubic centimetre,find the density in kilogram per cubic metre

wel

Answer:

1.42

Explanation:

devide 10 by 7

7 0

3 years ago

A 5 kg block is pushed across a table by a horizontal force of 40 N with an acceleration of 5 m/s^2. What is the frictional forc

julsineya [31]

Answer:

Explanation:

mass, M = 5Kg

horizontal force, F_h = 40N

acceleration, a =5 m/s^2

frictional force, F_f =?

net force = ma

net force = F_h - F_f = 40N - F_f

40 - F_f = 5 x 5

- F_f = 25 - 40

multiply both side by -1

F_f = 40 - 25 = 15

the frictional force is 15N

4 0

2 years ago

The wavelength of light that has a frequency of 1.20 × 1013 s-1 is ________ m.

klio [65]

The relationship between frequency and wavelength for an electromagnetic wave is
$c=f \lambda$
where
f is the frequency
$\lambda$ is the wavelength
$c=3 \cdot 10^8 m/s$ is the speed of light.

For the light in our problem, the frequency is $f=1.20 \cdot 10^{13} s^{-1}$ , so its wavelength is (re-arranging the previous formula)
$\lambda= \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{1.20 \cdot 10^{13} s^{-1}}= 2.5 \cdot 10^{-5}m$

8 0

2 years ago