Explanation:
Let us calculate the work done in lifting an object of mass m through a height h, such as in Figure 1. If the object is lifted straight up at constant speed, then the force needed to lift it is equal to its weight mg. The work done on the mass is then W = Fd = mgh. We define this to be the gravitational potential energy (PEg) put into (or gained by) the object-Earth system. This energy is associated with the state of separation between two objects that attract each other by the gravitational force
Potential energy is a property of a system rather than of a single object—due to its physical position. An object’s gravitational potential is due to its position relative to the surroundings within the Earth-object system. The force applied to the object is an external force, from outside the system. When it does positive work it increases the gravitational potential energy of the system. Because gravitational potential energy depends on relative position, we need a reference level at which to set the potential energy equal to 0. We usually choose this point to be Earth’s surface, but this point is arbitrary; what is important is the difference in gravitational potential energy, because this difference is what relates to the work done. The difference in gravitational potential energy of an object (in the Earth-object system) between two rungs of a ladder will be the same for the first two rungs as for the last two rungs.
1.) Product is a solid
2.) Product has flat slides
3.) Flat sides meet at sharp edges and corners
The product would be a crystal, or it would be a type of product in a crystal structure.
Answer:
Manometer is a measures to the atmospheric measure.
Barometer is a measure to the atmospheric pressure.
Explanation:
- Manometer is there are two types (1) closed tube (2) open tube, is filled with liquid water and mercury and the tube.
- Manometer do not need equal size of the tubes to the open ended manometers.
- Manometers is simple to attach on this filled to the high pressure gas in the bulb,this gas pressure put on the tube.
- Manometer is the attach the gas and vacuum gas to the open of the air, its high pressure gas is to the one of end.
- Manometer are filled the mercury to the heavy liquid manometer filled the liquid water and oil with the mercury.
- Barometer is to the close ended tube and the glass tube is the open and that a vacuum is the other end.
- Barometer can the u shaped and the closed ended tubes to the barometers.
- Barometer is the mercury closed end and vacuum is the tallest point in the liquid.
- Barometer is also used to be a table or left standing and also be digital and portable traditional glass, may find the digital clock .
- Barometer are filled the mercury to the high level liquid must be extreme tall in change in atmospheric pressure.
Answer:
100 A.
Explanation:
From the question given above, the following data were obtained:
Electrochemical equivalent (Z) = 0.0012 g/C
Mass (M) = 36 g
Time (t) = 5 mins
Current (I) =?
Next, we shall determine the charge. This can be obtained as follow:
Electrochemical equivalence (Z) = 0.0012 g/C
Mass (M) = 36 g
Charge (Q) =.?
M = ZQ
36 = 0.0012 × Q
Divide both side by 0.0012
Q = 36 / 0.0012
Q = 30000 C
Next, we shall convert 5 mins to s. This can be obtained as follow:
1 min = 60 s
Therefore,
5 mins = 5 × 60
5 mins = 300 s
Finally, we shall determine the current. This can be obtained as shown below:
Charge (Q) = 30000 C
Time (t) = 300 s
Current (I) =?
Q = It
30000 = I × 300
Divide both side by 300
I = 30000 / 300
I = 100 A
Therefore, the current is 100 A.