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Elden [556K]
3 years ago
7

Difference between relaxation time and collision time?

Physics
2 answers:
Black_prince [1.1K]3 years ago
6 0
For the answer to the question above, let us first start with relaxation time. it is the absence of an external electric field, the free electrons in a metallic substance will move in random directions so that the resultant velocity of free electrons in any direction is equal to zero. While the Collision time it is<span> the mean </span>time<span> required for the direction of motion of an individual type particle to deviate through approximately as a consequence of </span>collisions<span> with particles of type.</span>
Katyanochek1 [597]3 years ago
3 0

Answer:

Explanation:

Collision time is the average time that is required for a moving individual particle to change direction as a result of collision with particles of type.

Relaxation time is the time required for the amplitude of  an oscillating variable to drop from an initial value to 0.368 of that value. The average resultant velocity drops exponentially to zero in the absence of an electric field.

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Human cell has 46 chromosomes. At the end of mitosis, there are two cells, each with 46 chromosomes, for a total of 92 chromosom
Maslowich

Answer:

2.At the end of meiosis, there are four cells each with 23 chromosomes, for a total of 92 chromosomes split between the four cells.

5 0
3 years ago
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Calculate the phase angle (in radians) for a circuit with a maximum voltage of 12 V and w-50 Hz. The voltage source is connected
Vinvika [58]

Answer:

The phase angle is 0.0180 rad.

(c) is correct option.

Explanation:

Given that,

Voltage = 12 V

Angular velocity = 50 Hz

Capacitance C= 20\times10^{-2}\ F

Inductance L=20\times10^{-3}\ H

Resistance R=  50\ Omega

We need to calculate the impedance

Using formula of impedance

z=\sqrt{R^2+(\omega L-\dfrac{1}{\omega C})^2}

z=\sqrt{50^2+(50\times20\times10^{-3}-\dfrac{1}{50\times20\times10^{-2}})^2}

z=50.00

We need to calculate the phase angle

Using formula of phase angle

\theta=\cos^{-1}(\dfrac{R}{z})

\theta=\cos^{-1}(\dfrac{50}{50.00})

\theta=0.0180\ rad

Hence, The phase angle is 0.0180 rad.

3 0
4 years ago
Three batteries are connected in series so that the total voltage is 54 volts. The voltage of the first battery is twice the vol
Alex_Xolod [135]

Answer:

v_1 = 12 volts

v_2 = 6 volts

v_3 = 36 volts

Explanation:

As we know that all the batteries are in series

so the net voltage of all three batteries is given as

V = v_1 + v_2 + v_3

now we know that

v_1 = 2v_2

v_1 = \frac{1}{3}v_3

now plug in all the values in it

54 = v_1 + \frac{v_1}{2} + 3v_1

54 = 4.5 v_1

v_1 = 12 volts

now we have

v_2 = 6 volts

v_3 = 36 volts

3 0
3 years ago
What is the electric force acting between two charges of 0.0042 C and −0.0050 C that are 0.0030 m apart?
Black_prince [1.1K]

Answer:

A.−2.1 × 10^10 N

Explanation:

Using the formula;

E = k Q1Q2/d²

Where;

E is the electrical force  

k is the constant  

Q1, Q2 are the two charges  and

d is the distance between the two charges

Therefore;

E = (9 x 10^9) × (0.0042) × (-0.0050) / (0.0030)²  

 = -2.1 x 10^10 N

Therefore; electrical force acting between the two charges is -2.1 x 10^10 N.

6 0
4 years ago
A stone is launched from the ground, at a 70° angle, with an initial velocity of 120 m/s.
zavuch27 [327]
<span>A) x = 41t
    The classic equation for distance is velocity multiplied by time. And unfortunately, all of your available options have the form of that equation. In fact, the only difference between any of the equations is what looks to be velocity. And in order to solve the problem initially, you need to divide the velocity vector into a vertical velocity vector and a horizontal velocity vector. And the horizontal velocity vector is simply the cosine of the angle multiplied by the total velocity. So H = 120*cos(70) = 120*0.34202 = 41.04242 So the horizontal velocity is about 41 m/s. Looking at the available options, only "A" even comes close.</span>
3 0
3 years ago
Read 2 more answers
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