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Olin [163]
3 years ago
9

This direct relationship graph shows that the position of the car as time elapses.

Physics
1 answer:
Sophie [7]3 years ago
5 0

Answer:

Increases is the correct answer.

Explanation:

Just took the quiz.

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A person walks 2.00 m east, then turns and goes 4.00 m west, then turns and goes back 1.00 m east.
bekas [8.4K]

Answer:

i got -1.00

Explanation:

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3 years ago
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What is the unit of work? (select all that apply) *
galina1969 [7]

Answer:

Joule is the answer

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3 years ago
You rubbed two identical balloons in your hair's friend. This causes the balloons to become charged negatively with a magnitude
dem82 [27]

Answer:

a)  F = 2.25 10³ N, b) REPULSIVE.

Explanation:

a) The electric force is given by coulomb's law

           F = k \frac{q_1q_2}{r^2}k q1q2 / r2

in this case nso indicate that the two charges have the same value

           q₁ = q₂ = 2.5 10⁻⁶ C

Let's reduce the magnitudes to the SI system

           r = 0.5 cm (1m / 100cm) = 5 10⁻³ m

let's calculate

           F = 9 \ 10^9 \frac{(2.5 \ 10^{-6})^2 }{(5 \ 10^{-3})^2}

           F = 2.25 10³ N

b) In electricity, electric charges of the same sign repel and those of the opposite sign attract

In this exercise, the balls are equal and are rubbed with the same material, for which it acquires charges of the same type, consequently, as the charges are of the same type, they indicate that the negative force is REPULSIVE.

7 0
3 years ago
A glider of mass m1 on a frictionless horizontal track is connected to an object of mass m2 by a massless string. The glider acc
inysia [295]

Answer:

m2g -> T2 -> T1

Explanation:

m2g -> T2 -> T1

5 0
4 years ago
Durante un intento juego de croquet, una bola de 0.52 kg en reposo sobre el cesped es golpeada por un mazo con una fuerza promed
Romashka [77]

Answer: 2.63 m/s

Explanation:

The question in english is written below:

During an attemp of croquet game, a 0.52 kg ball at rest on the grass is hit by a mallet with an average force of 190 N, if the mallet is in contact with the ball for 7.2(10)^{-3} s,  Whay is the speed of the ball just after being hit?

According to Newton's second law of motion, the force F exerted on an object is directly proportional to its mass m and acceleration a:

F=m.a (1)

On the other hand, acceleration is defined as the variation of velocity V in time t:

a=\frac{V}{t} (2)

Substituting (2) in (1):

F=m\frac{V}{t} (3)

Where:

F=190 N

m=0.52 kg

t=7.2(10)^{-3} s

Isolating the velocity V from (3):

V=\frac{Ft}{m} (4)

V=\frac{(190 N)(7.2(10)^{-3} s)}{0.52 kg}

Finally:

V=2.63 m/s

6 0
4 years ago
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